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Verdich [7]
3 years ago
7

H=-5 and w=2, work out the value of 4h-3w

Mathematics
2 answers:
inn [45]3 years ago
7 0
4(-5)-3(2)
-20-6
-26=answer
olganol [36]3 years ago
3 0
You would simply have to plug in, or substitute, the given values in the equations.

So, H=-5, W=2 and the problem is 4h-3w

To plug them in, your new equation would be 4(-5)-3(2) and simplify. So it becomes -20-6 which = -26. 

And -26 would be your answer.
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Solve 11 ≤ w + 3.4 i dont know the answer please help me
shepuryov [24]

Answer:

7.6 ≤w

Step-by-step explanation:

Hey there!

In order to solve this inequality, you need to simplify the inequality like the following:

Subtract 3.4 from both sides

7.6 ≤w

This means that w is greater than or equal to 7.6

6 0
2 years ago
4k + 12 = 52<br> using algbra
grigory [225]

Answer:

k=10

Step-by-step explanation:

4k + 12= 52

minus 12 on both sides

4k=40

now divide by 4

k=10

5 0
3 years ago
Which inequality is NOT true if y = -5?
sertanlavr [38]

Answer:

c is the answer

Step-by-step explanation:

solution

3y + 9 \geqslant  - 15

3( - 5) + 9 \geqslant  - 15

- 15 + 9 \geqslant  - 15

- 6 \geqslant  - 15

therefore the equation is not true

6 0
3 years ago
PLEASE HELP ME
denis23 [38]

Answer:

(1) The possible outcomes are: X = {0, 1, 2, 3}.

(2) The number of times should Hartley spin a difference of 1 is 36.

(3) The number of times should Hartley spin a difference of 0 is 24.

Step-by-step explanation:

The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.

The total number of spins for each of the spinner is, <em>n</em> = 96.

(1)

The sample space of spinning both the spinners together are:

S = {(1, 1), (1, 2), (1, 3), (1, 4)

      (2, 1), (2, 2), (2, 3), (2, 4)

      (3, 1), (3, 2), (3, 3), (3, 4)

      (4, 1), (4, 2), (4, 3), (4, 4)}

Total = 16.

The possible outcomes are:

X = {0, 1, 2, 3}.

(2)

The sample space with the difference 1 are:

S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}

n (S₁) = 6

The probability of the difference 1 is:

P(\text{Diff}=1)=\frac{n(S_{1})}{N}=\frac{6}{16}=\frac{3}{8}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 1 is:

E(\text{Diff}=1)=P(\text{Diff}=1)\times n\\\\=\frac{3}{8}\times 96\\\\=36

Thus, the number of times should Hartley spin a difference of 1 is 36.

(3)

The sample space with the difference 0 are:

S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}

n (S₂) = 4

The probability of the difference 0 is:

P(\text{Diff}=0)=\frac{n(S_{2})}{N}=\frac{4}{16}=\frac{1}{4}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 0 is:

E(\text{Diff}=0)=P(\text{Diff}=0)\times n\\\\=\frac{1}{4}\times 96\\\\=24

Thus, the number of times should Hartley spin a difference of 0 is 24.

4 0
3 years ago
A 12500 loan for 3 years compounded at an annual interest rate of 18%
mafiozo [28]
It would be $ 6,750 or a total of  $19,250 
7 0
3 years ago
Read 2 more answers
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