Which of the following is the most accurate statement about Spatial Relations?

1 answer:

8 0

Option C. The correct statement about spatial relationshipo is that Spatial terms such as above, below, behind, and under are used to describe objects in space.

<h3>What are spatial relationship?</h3>

These are the types of relationships that are used to relate objects to the location of somethings else. It makes use of words like under, above etc.

It is one of the knowledge that children need in the preoperational stage to learn how to use logical operations.

Read more on spatial relationships here:

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Points representing the length if a rectangle are located at A(0,0) and B(8,0). The width of the rectangle is one half its lengt

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Simplify the expression 3/2 (5/3) -1 1/4 + 1/2 Given the answer as a simplified fraction. The simplified expression is a/b.

ella [17]

<h2>Hello!</h2>

The answer is:

The simplified fraction is:

$\frac{7}{4}$

To solve this problem we must remember the following:

- Addition or subtraction of fractions, we add or subtract fractions by the following way:

$\frac{a}{b}(+-)\frac{c}{d}=\frac{ad(+-)bc}{bd}$

- Product of fractions, the multiplication of fraction is linear, meaning that we should multiply the numerator by the numerator and denominator by denominator, so:

$\frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}$

- Convert mixed number to fraction,

$a\frac{b}{c}=a+\frac{b}{c}=\frac{ac+b}{c}$

So, solving we have:

$\frac{3}{2}*\frac{5}{3}-1\frac{1}{4}+\frac{1}{2}=\frac{3*5}{2*3} -1\frac{1}{4}+\frac{1}{2}\\\\\frac{3*5}{2*3} -1\frac{1}{4}+\frac{1}{2}=\frac{15}{6} -1\frac{1}{4}+\frac{1}{2}\\\\\frac{15}{6} -1\frac{1}{4}+\frac{1}{2}=\frac{15}{6} -(1+\frac{1}{4})+\frac{1}{2}\\\\\frac{15}{6} -(1+\frac{1}{4})+\frac{1}{2}=\frac{15}{6}-(\frac{4+1}{1*4})+\frac{1}{2}\\\\\frac{15}{6}-(\frac{4+1}{4})+\frac{1}{2}=\frac{15}{6}-\frac{5}{4}+\frac{1}{2}$

$\frac{15}{6}-\frac{5}{4}+\frac{1}{2}=(\frac{5}{2}-\frac{5}{4})+\frac{1}{2}\\\\(\frac{5}{2}-\frac{5}{4})+\frac{1}{2}=(\frac{(4*5)-(2*5)}{8})+\frac{1}{2}\\\\(\frac{(4*5)-(2*5)}{8})+\frac{1}{2}=(\frac{20-10}{8})+\frac{1}{2}\\\\(\frac{20-10}{8})+\frac{1}{2}=(\frac{10}{8})+\frac{1}{2}\\\\(\frac{10}{8})+\frac{1}{2}=\frac{5}{4}+\frac{1}{2}\\\\\frac{5}{4}+\frac{1}{2}=\frac{(5*2)+(4*1)}{2*4}\\\\\frac{(5*2)+(4*1)}{2*4}=\frac{10+4}{8}=\frac{14}{8}\\\\\frac{14}{8}=\frac{7}{4}$