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3 years ago

How tall is a stack of ten pennies in centimeters?

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

6 0

we know that

The Penny is the one cent coin of the United States.The coin is 19.05 millimeters in diameter and 1.52 millimeters thick.

the height of a stack of ten pennies is equal to

$10*1.52=15.2 mm$

to convert mm to cm divide by $10$

$\frac{15.2}{10} =1.52cm$

therefore

the answer is

$1.52 cm$

disa [49]3 years ago

4 0

A penny is 1.52 mm, so 10 pennies are 15.2 mm. 15.2 mm=1.52 cm
So a stack of 10 pennies is 1.52 centimeters

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Jessie has rewritten the quadratic equation x2-32x +54 -0 in the form (-p) = 202. What is the value of p in the rewritten equati

ivolga24 [154]

Given:

The quadratic equation is:

$x^2-32x+54=0$

It can be written as $-p=202$ .

To find:

The value of p in the rewritten equation.

Solution:

We have,

$x^2-32x+54=0$

Isolate the constant term.

We need to make 202 on the right side. So, add 256 on both sides.

$x^2-32x+256=-54+256$

$x^2-32x+256=202$

$-(-x^2+32x-256)=202$

Let $-x^2+32x-256=p$ , then

$-p=202$

Therefore, the value of p is $-x^2+32x-256$ .

The given equation can be written as:

$54=-x^2+32x$

Adding 148 on both sides, we get

$54+148=-x^2+32x+148$

$202=-(x^2-32x-148)$

Let $x^2-32x-148=p$ , then

$202=-p$

Therefore, the another possible value of p is $x^2-32x-148$ .

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2 years ago

The living room dimensions of a new house are 12' 2" and 10'6".

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127.8. (12.2 =146 sq inches. 10.6 = 126 square inches. 146x126=18,396 square inches. 18,396/144 (144 square inches in a square foot) is 127.75 square feet).

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2 years ago

Define energy .....?

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Step-by-step explanation:

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2 years ago

The Garden Task

Igoryamba

If the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:

the perimeter = 24 ft
the area = 36 sq. ft
if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
if the area of the garden is doubled, the area of the new garden = 72 sq. ft

Recall:

A square has equal side lengths
Perimeter of a square = 4(side length)
Area of a square = $(side $ length)^2$

Given:

Perimeter of square (P) = $(14x - 32) $ ft$

Side length (s) = $(x + 2) $ ft$

First, let's find the value of x by creating an equation using the perimeter formula:

Perimeter of a square = 4(side length)

Plug in the values

$(14x - 32) = 4(x + 2)$

Solve for x

$14x - 32 = 4x + 8\\\\14x - 4x = 32 + 8\\\\10x = 40\\\\x = 4$

Find how much fencing would be needed (Perimeter of the fence):

Perimeter of the fence = $(14x - 32) $ ft$

Plug in the value of x

Perimeter of the fence = $14(4) - 32 = 24 $ ft$

Find the area of the garden:

Area of the garden = $(side $ length)^2$

Area = $(x + 2)^2$

Plug in the value of x

Area = $(4 + 2)^2 = 6^2 = 36 $ ft^2$

Find the perimeter if the garden size is doubled:

Perimeter of the new garden = 2 x 24 = 48 ft

Find the area if the garden size is doubled:

Perimeter of the new garden = 2 x 36 = 72 sq. ft

In summary, if the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:

the perimeter = 24 ft
the area = 36 sq. ft
if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
if the area of the garden is doubled, the area of the new garden = 72 sq. ft

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