Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
Answer:
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Step-by-step explanation:
1.75 gallons of water because one gallon holds 16 cups of water.
Solution: We are given below data:
Now to find the mean deviation, we use the below formula:
Where:
represents the summation
X, represents the observation.
represents the mean
N represents the number of observation.
Therefore, the mean deviation is:
= 4
Answer:
2 % amount = 12000 7% amount = 1000 dollars
Step-by-step explanation:
x = 2% amount
then 13 000 - x = 7% amount
.02x + .07 (13000-x) = 310
-.05x + 910 = 310
.05x = 600
x = 600/.05 = 12000 then the 7% amount is 1000
