Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F = 
where k= 
So , 2.2 = ( 
So , q ² = (
)
For charge magnitude
I.e q ² = 
so, q = 
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer
Answer:
r = 7.1 cm
Step-by-step explanation:
Given the following data;
Volume of hemisphere = 757 cm³
To find the radius of the hemisphere;
Mathematically, the volume of a hemisphere is given by the formula;
Volume of hemisphere = ⅔πr³
Where, r is the radius of the hemisphere.
π = 22/7
Substituting into the formula, we have;
757 = ⅔πr³
Cross-multiplying, we have;
757 * 3 = 2πr³
2271 = 2*22/7*r³
2271 = 44/7*r³
Cross-multiplying, we have;
2271 * 7 = 44r³
15897 = 44r³
r³ = 15897/44
r³ = 361.30
Taking the cube root of both sides, we have;
r = 7.1223
To the nearest tenth of a centimeter;
r = 7.1 cm
Answer:
0
Step-by-step explanation:
Answer:
Hence, 87,50,000 can be expressed as 
.
Step-by-step explanation:
- Given 87,50,000
- Use given, move the decimal point so that first factor is greater than or equal to 1 but less than 10 .
- Then count n and write in scientific notation.
Step 1 of 1
Consider 87,50,000.
8.75
So, 8.75 lies between 1 & 10 .
Now, Decimal moved to 6 places at left.
So, 
.
She Bought 23 shirts because if you do 400-50 you get 350 the / by 15 wich give you 23.333333ect
