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Mekhanik [1.2K]
3 years ago
6

I don't understand what the pattern is here.

Mathematics
2 answers:
Tanzania [10]3 years ago
7 0
Jhgiokkhyfcvnshwhwuagsgwhwwu
vladimir2022 [97]3 years ago
4 0

b b. &hhhgzyzyzudududi. jcjcfificicicifif

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Solutions of the equation: z2 - 12z + 36 = 0?
jasenka [17]
36 becomes a negative 

First -36 + -1 -37
Next: -18 + -2 = -20 
Next: -12 + -3 = -15
Next: -9 + -4 which equals -13
Finally we get to the last part: -6 + -6 = -12

We change z2 to z^{2}

z^{2} - 6(z) = 36 

z(z) - 6

Because, we add up for the first two terms

Switch up, up the problem 6(z) - 6

Now, let's add the number 4 on the terms 
z - 6 (z - 6) 

Then, let's multiply z - 6 from z - 6 

z - 6^{2} = ? 


From this problem we have to add 6 from the sides that we are working with 

Therefore, your answer for z is 6 
7 0
3 years ago
What simplified Rayo correctly compares 36 inches to 4 feet
Rudiy27
The answer is 8 to 1 because divide 36to4 that equals 8 then4 divide to 4 its 1
6 0
3 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
What are the solutions to the equation (x – 6)(x + 8) = 0?
VikaD [51]

Answer:

x=6, x=-8

Step-by-step explanation: i used the symbolab calculator online to solve this.

3 0
3 years ago
Read 2 more answers
Given the triangle below, what is the length of the third side, rounded to the nearest whole number?
Leno4ka [110]

Answer:

Step-by-step explanation:

You need the Law of Cosines for this, namely:

x^2=21^2+14^2-2(21)(14)cos58 where x is the missing side.

x^2=441+196-311.5925 and

x^2=325.4075 so

x = 18.0 or just 18

7 0
3 years ago
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