Question

The expression (y^20) (y^-5)^2 is equivalent to y^n. What is the value of n? n = 27 n = 10 n = -200 n = 17

Answer 1

Answer:

n = 10

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

$(a^{m}) ^{n}$ = $a^{mn}$

Given

($y^{20}$ ) ($(y^{-5}) ^{2}$

= $y^{20}$ × $y^{-10}$

= $y^{(20-10)}$

= $y^{10}$ → in the form $y^{n}$ with n = 10