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jolli1 [7]
3 years ago
10

For f(x)=0.01(2)power of x, find the average rate of change from x=3 to x=8

Mathematics
1 answer:
sineoko [7]3 years ago
4 0
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= 0.01(2)^x  \qquad 
\begin{cases}
x_1=3\\
x_2=8
\end{cases}\implies \cfrac{f(8)-f(3)}{8-3}
\\\\\\
\cfrac{0.01(2)^8-0.01(2)^3}{8-3}
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So what we do is
area that remains=total area-triangle area that was cut out


we need to find 2 things
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total area=rectange=base times height
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FOIL or distribute
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so
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6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
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