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Irina-Kira [14]
3 years ago
9

I don't understand this, can someone help?

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

It is less than 1 because .31 + 5/9   < 1

Step-by-step explanation:

.31 - (-5/9)

.31 + 5/9

31/100 + 5/9

estimating

1/3 + 2/3

this is approximately 1

but 1/3 = .33333333  is greater than .31 and 2/3  = 6/9  is greater than 5/9

so .31 + 5/9 < 1

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2.5 - 8 = 5.5
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8×7×3 nooooooooooooooow
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Answer:

168

Step-by-step explanation:

Simply multiply the 3 digits

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Solve by Substitution. <br> 3x+2y=-4 <br> y=4x-2
qwelly [4]

x=0

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Use the quadratic formula to find the solutions to the equation x^2-3x+1=0
Gnom [1K]

Answer:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

Step-by-step explanation:

Using:

x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}

we will have two solutions.

x^2-3x+1=0

So, a=1   b=-3  c=1

x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}

We have two solutions:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

4 0
3 years ago
What’s the probability of getting each card out of a deck?
VMariaS [17]

Answer:

a. 1/13

b. 1/52

c. 2/13

d. 1/2

e. 15/26

f. 17/52

g. 1/2

Step-by-step explanation:

a. In a deck of cards, there are 4 suits and each of them has a 7. Therefore, the probability of drawing a 7 is:

P(7) = 4/52 = 1/13

b. There is only one 6 of clubs, therefore, the probability of drawing a 6 of clubs is:

P(6 of clubs) = 1/52

c. There 4 fives (one for each suit) and 4 queens in a deck of cards. Therefore, the probability of drawing a five or a queen​​​​​​​​​​​ is:

P(5 or Q) = P(5) + P(Q)

= 4/52 + 4/52

= 1/13 + 1/13

P(5 or Q) = 2/13

d. There are 2 suits that are black. Each suit has 13 cards. Therefore, there are 26 black cards. The probability of drawing a black card is:

P(B) = 26/52 = 1/2

e. There are 2 suits that are red. Each suit has 13 cards. Therefore, there are 26 red cards. There are 4 jacks. Therefore:

P(R or J) = P(R) + P(J)

= 26/52 + 4/52

= 30/52

P(R or J) = 15/26

f. There are 13 cards in clubs suit and there are 4 aces, therefore:

P(C or A) = P(C) + P(A)

= 13/52 + 4/52

P(C or A) = 17/52

g. There are 13 cards in the diamonds suit and there are 13 in the spades suit, therefore:

P(D or S) = P(D) + P(S)

= 13/52 + 13/52

= 26/52

P(D or S) = 1/2

6 0
3 years ago
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