We use different models for different types of variation. For example, linear variation is associated with the formula y=ax, or the more familiar y=mx+b (the equation of a straight line). Cubic variation: y=a*x^3. In the present case we're discussing quadratic variation; perhaps that will ring a bell with you, reminding you that y=ax^2+bx+c is the general quadratic function. Now in y our math problem, we're told that this is a case of quadratic variation. Use the model y=a*x^2. For example, we know that if x=2, y =32. Mind substituting those two values into y=a*x^2 and solving for y? Then you could re-write y=a*x^2 substituting this value for a. Then check thisd value by substituting x=3, y=72, and see whether the resulting equation is true or not. If it is, your a value is correct. But overall I got 16!

7 0

4 years ago

The table shows the solution to the equation|2x-5|-2=3: which is the first step

Anastaziya [24]

|2x - 5| - 2 = 3 |add 2 to both sides

|2x - 5| = 5 ⇔ 2x - 5 = 5 or 2x - 5 = -5 |add 5 to both sides

2x = 10 or 2x = 0 |divide both sides by 2

x = 5 or x = 0

5 0

3 years ago