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IgorC [24]
3 years ago
9

Convert 42 km/h to m/s

Mathematics
1 answer:
Marta_Voda [28]3 years ago
5 0

42 km/h is equal to 0.00724933 m/s

You get this by dividing the km/h speed value by 1.609 to get it to m/h, then divide that by 60, then by 60 again to get it to m/s.

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How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
allochka39001 [22]

Answer:

I think b) is the answer I solve it but

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2 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
3 years ago
What is x and y using substitution
Bad White [126]
X-5y=36
x+y=-26

y=-26-x

x-5(-26-x)=36
x+130+x=36
2x+130=36
2x=36-130
2x=-94
x=47
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sergiy2304 [10]
I think the answer is c im not sure sorry
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Answer:

Tationia Rolon

Step-by-step explanation:

$52.08

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