n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.
Since these are solutions
x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.
We have (x-2)(x-5i)(x+5i) = 0
Now,
f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.
f(-1) = (-3)(26) = -78.
But -78 x -2 = 156, so our polynomial becomes
Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0
the circle has a diameter of 12, thus its radius is half that, or 6.
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Step-by-step explanation:
Hope this helps, happy studying!
Answer:
y=-3x-13
Step-by-step explanation:
Plug in the -2 and -4 for the y and x. The slope is the same
1) -4 = -3 (-3)+b
2) -4=9+b
3) -4-9=b
4) -13=b
The equation is y=-3x-13