Answer:
Step-by-step explanation:
We want to create a third degree polynomial function with one zero at three.
In other words, we want to find a polynomial function with roots x=3 , multiplicity, 3.
Since x=3 is a solution, x-3 is the only factor that repeats thrice.
We expand to get:
This simplifies to:
See attachment for graph.
Answer: 
Step-by-step explanation:
The expression can be simplified by applying the a properties of exponents, specifically the Product of powers, which states that:
Where b is the base and a and c are exponents.
Then simplify it by rewriting the base (
) and adding the exponents of the expression (8 and 9).
You will get the expression simplified and written as a power:
If I'm doing this right, I'm pretty sure the answer would be 7, since 0 + 1 = 1, 8 - 1 = 7, and 7 x 1 = 7.
I hope this answer helped you! If you have any further questions or concerns, feel free to ask! :)
When we factorise an expression, we are looking for simple factors that multiply to get the original expression. Usually it is very natural to factorise something like a quadratic in x. For example:
x^2 + 3x + 2 = (x+1)(x+2)
But there are other situations where factorisation can be applied. Take this quadratic:
x^2 - 9x = x(x-9)
This second example is closer to the question in hand. Just like x was a common factor to both x^2 and -9x, we are looking for a common factor to both 6b and 24bc. The common factor is 6b.
Hence 6b + 24bc = 6b(1 + 4c).
I hope this helps you :)
Answer:
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Step-by-step explanation:
she refuses to pay because the owners of the place shes living is supposed to fix damage and they have not done so she refuses to pay the rent.
