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4 years ago

Ninety percent of what number is 45

Mathematics

1 answer:

hram777 [196]4 years ago

7 0

Divide 45 by 90%
45÷0.90=50

Check your work:
=50*90%
=50*0.90
=45

45 is 90% of 50

Hope this helps! :)

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A rectangular cracker has a length of 5 centimeters and an area f 20 square centimeters. Find its perimeter.

iren [92.7K]

Answer:

18cm

Step-by-step explanation:

We have the length of the rectangle but we need to find the width which we'll call w. Area is a, l is length.

a = l * w

20 = 5 * w

divide both sides by 5 to cancel the multiplication by 5 on the right side

4 = w

The rectangle is going to have two sides that are the length of l, and two sides that are the the length of w. We're looking for the perimiter p.

p = 2l + 2w

p = (2 * 5) + (2 * 4)

p = 18

4 0

2 years ago

Each circle counts as one whole. Write a mixed number giving the amount shaded. Then, write this amount as an improper fraction.

ryzh [129]

Answer: 1 3/4 is your mixed fraction and 7/4 is the improper fraction.

Step-by-step explanation:

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3 years ago

Find the circumference of a circle with each 18.2cm diameter

e-lub [12.9K]

Answer:

22/7×18.2

=400.4/7

=57.2cm

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3 years ago

Find the quotient of -85^2-27n+76 / -17n-19

bagirrra123 [75]

Answer:
5n-4

Explanation:
The given expression is:
$\frac{-85n^2-27n+76}{-17n-19}$

1- Take the negative as a common factor from both the numerator and the denominator. This will give us:
$\frac{-(85n^2+27n-76)}{-(17n+19)}$

2- Cancel out the negative sign (common factor) from the numerator and denominator. This will give us:
$\frac{(85n^2+27n-76)}{(17n+19)}$

3- Factor the numerator. This wil give:
$\frac{(5n-4)(17n+19)}{(17n+19)}$

4- Finally, cancel out the (17n+19) which common in both numerator and denominator. This will give us the final expression:
5n-4

Hope this helps :)

6 0

3 years ago

How can I solve this problem?

irina [24]

5x + 5x +3x (like terms)
13x-60=180
180+60=240
240/13=18.4615
X=18.4615

I hope this is correct.
(There are so many different ways to do math problems like this) I hope I could help... sorry if I didn’t.

6 0

3 years ago