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sashaice [31]
3 years ago
14

How can I solve this problem?​

Mathematics
1 answer:
irina [24]3 years ago
6 0
5x + 5x +3x (like terms)
13x-60=180
180+60=240
240/13=18.4615
X=18.4615

I hope this is correct.
(There are so many different ways to do math problems like this) I hope I could help... sorry if I didn’t.
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Suppose you want to place a shelf that is 30 1/3 inches long in the center of a wall that is 45 3/4 inches wide. About how fare
mrs_skeptik [129]

Answer:

7.71 inches far from each edge of the wall you should place the shelf.

Step-by-step explanation:

Given:

\textrm{size of a shelf}=30\frac{1}{3} =\frac{91}{3}=30.33\ inches\\\textrm{size of a wall}=45\frac{3}{4} =\frac{183}{4}=45.75\ inches\\

Let,

AB = distance between the edges or distance of wall.

ED = size of the shelf.

C is the centre of the wall.

To Find:

Distance from the edge of the wall to the shelf, when the shell is placed at the center of the wall.

AE = DB = ?

Solution:

As we need to place the shelf exactly in the center.

First we will calculate the  distance from the center of the wall to the edge.

So the distance from the centre of the wall to the edge will be exactly half of the size of the wall.

CB = \frac{1}{2}\times AB\\ =\frac{1}{2}\times 45.75\\\therefore CB=22.875\ inches

now the distance from the centre to the end of the shelf will be exactly half of the size of the shelf.

CE = \frac{1}{2}\times DE\\ =\frac{1}{2}\times 30.33\\\therefore CB=15.165\ inches

Now we want to calculate the distance from the edge of the wall to the shelf,that is the distance from the end of the shelf to the edge of the wall.

AE=BD= BC-CD\\=22.875-15.165\\=7.71\ inches\\\therefore AE = BD = 7.71\ inches

Therefore, 7.71 inches far from each edge of the wall you should place the shelf.

5 0
3 years ago
Before we can make the mashed potatoes, we need to boil some water. The water starts out at room temperature, 70° F, and increas
Karolina [17]

Answer:

Part a) y=50t+70

Part b) t=2.84\ min

Step-by-step explanation:

Part a) Create a linear equation

Let

t ----> the time in minutes

y ---> the temperature in °F

we know that

The linear equation in slope intercept form is equal to

y=mt+b

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

In this problem we have

The slope m is equal to

m=50\° F\ per\ minute

The y-intercept is

b=70\° F

substitute

y=50t+70

Part b) How many minutes until the water boils at 212° F?

For y=212° F

substitute in the linear equation and solve for t

212=50t+70

50t=212-70

50t=142

t=2.84\ min

6 0
3 years ago
In △ABC AL is an angle bisector (L∈ BC ). Point M∈ AB so that LM=AM=BM. Find the angles in △ABC, if AC=2AL.
Diano4ka-milaya [45]

If AM=BM, then point M is a middle point of side AB.

1. Consider triangle AML. You know that AM=ML, then this triangle is isosceles and AL is its base. The angles adjacent to the base of isosceles triangle are conruent, this means that \angle MAK\cong \angle AML.

2. Consider lines ML and AC. The angle bisector AL is transversal. Since alternate interior angles \angle MAK\cong \angle AML, you have that lines ML and AC are parallel. This means that ML is a middle line of triangle and 2ML=AC. Also you know that AC=2AL. This gives you that ML=AL. Now ML=AL and ML=AM gives you that triangle AML is equilateral.

3. In equilateral triangle AML all angles are congruent and have measures 60°. Thus, m∠AML=m∠MLA=m∠LAM=60°.

4. AL is angle bisector, then m∠MAL=m∠LAC=60° and m∠BAC=m∠MAL+m∠LAC=120°.

5. Consider ΔBML, it is isosceles, because BM=ML and m∠BML=180°-m∠AML=180°-60°=120°. Then,

m\angle MBL=m\angle MLB=\dfrac{180^{\circ}-120^{\circ}}{2}=30^{\circ}.

6. Consider triangle ABC. In this triangle m∠A=120°, m∠B=30°, then

m∠C=180°-m∠A-m∠B=180°-120°-30°=30°.

Answer: m∠A=120°, m∠B=m∠C=30°.

3 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for f(x)=2x/x+4
lesya [120]

ANSWER

Vertical asymptote: x=-4

Horizontal asymptote: y=2

EXPLANATION

The given equation is

f(x) =  \frac{2x}{x + 4}

The vertical asymptote is determined by equating the denominator to zero and solve for x.

x + 4 = 0

The equation of the vertical asymptote is

x =  - 4

The numerator has the same degree as the denominator.

The equation of the horizontal asymptote is the coefficient of the leading term in the numerator expressed over the coefficient of the leading term in the denominator.

y =  \frac{2}{1}

y=2

5 0
4 years ago
When graphing a system (2 or more) inequalities, the solution set is where the shading on the graph overlaps.
dexar [7]
The Correct answer is true
5 0
3 years ago
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