Answer:
7.71 inches far from each edge of the wall you should place the shelf.
Step-by-step explanation:
Given:
Let,
AB = distance between the edges or distance of wall.
ED = size of the shelf.
C is the centre of the wall.
To Find:
Distance from the edge of the wall to the shelf, when the shell is placed at the center of the wall.
AE = DB = ?
Solution:
As we need to place the shelf exactly in the center.
First we will calculate the distance from the center of the wall to the edge.
So the distance from the centre of the wall to the edge will be exactly half of the size of the wall.
now the distance from the centre to the end of the shelf will be exactly half of the size of the shelf.
Now we want to calculate the distance from the edge of the wall to the shelf,that is the distance from the end of the shelf to the edge of the wall.
Therefore, 7.71 inches far from each edge of the wall you should place the shelf.
Answer:
Part a) 
Part b) 
Step-by-step explanation:
Part a) Create a linear equation
Let
t ----> the time in minutes
y ---> the temperature in °F
we know that
The linear equation in slope intercept form is equal to
where
m is the slope or unit rate of the linear equation
b is the y-intercept or initial value of the linear equation
In this problem we have
The slope m is equal to
The y-intercept is
substitute
Part b) How many minutes until the water boils at 212° F?
For y=212° F
substitute in the linear equation and solve for t
If AM=BM, then point M is a middle point of side AB.
1. Consider triangle AML. You know that AM=ML, then this triangle is isosceles and AL is its base. The angles adjacent to the base of isosceles triangle are conruent, this means that 
2. Consider lines ML and AC. The angle bisector AL is transversal. Since alternate interior angles 
you have that lines ML and AC are parallel. This means that ML is a middle line of triangle and 2ML=AC. Also you know that AC=2AL. This gives you that ML=AL. Now ML=AL and ML=AM gives you that triangle AML is equilateral.
3. In equilateral triangle AML all angles are congruent and have measures 60°. Thus, m∠AML=m∠MLA=m∠LAM=60°.
4. AL is angle bisector, then m∠MAL=m∠LAC=60° and m∠BAC=m∠MAL+m∠LAC=120°.
5. Consider ΔBML, it is isosceles, because BM=ML and m∠BML=180°-m∠AML=180°-60°=120°. Then,
6. Consider triangle ABC. In this triangle m∠A=120°, m∠B=30°, then
m∠C=180°-m∠A-m∠B=180°-120°-30°=30°.
Answer: m∠A=120°, m∠B=m∠C=30°.
ANSWER
Vertical asymptote: x=-4
Horizontal asymptote: y=2
EXPLANATION
The given equation is
The vertical asymptote is determined by equating the denominator to zero and solve for x.
The equation of the vertical asymptote is
The numerator has the same degree as the denominator.
The equation of the horizontal asymptote is the coefficient of the leading term in the numerator expressed over the coefficient of the leading term in the denominator.
y=2
