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3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

zhuklara [117]3 years ago

5 0

Answer:

see below

Step-by-step explanation:

9 ^-5 * 9^-3

When multiplying these we ADD the exponents:

9^-5 * 9^-3

= 9^(-5 + -3)

= 9 ^-8

= 1/9^8 Option A

2. 2^14 / 2^7 This is a division so we SUBTRACT the exponents:-

= 2^(14 - 7)

= 2^7 (answer)

3. If the triangle is a right angled one then it will obey Pythagoras Theorem so:-

13^ = x^2 + 5&2

x^2 = 13^2 - 5^2

x^2 = 144

x = 12 (answer)

4. The last choice is a crucial step.

The total area of the triangles is the same in both large squares so the area of the large square e^2 = a^2 + b^2 ( the 2 squares in the left side large square).

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Find the value of x so that (x,-4) is on the line given by -2x + 3y = 6.

lord [1]

Answer:

Step-by-step explanation:

-2x + 3y = 6.....(x, -4)...so y = -4

-2x + 3(-4) = 6

-2x - 12 = 6

-2x = 6 + 12

-2x = 18

x = -18/2

x = -9

so the value of x is -9.....(-9,-4)

6 0

3 years ago

Create a proportional ratio to the given ratio:<br> 2/4 is equal to what?

sladkih [1.3K]

Answer:

4/8, 6/12, 7/14,etc.

Step-by-step explanation:

Multiply 2/4 by any number(like 4) and you can find a equal ratio

5 0

3 years ago

Which statement describes whether a right triangle can be formed using one side length from each of these squares?

balu736 [363]

Answer:

Step-by-step explanation:

The area of the given squares are

Area = 64 in

Area = 225 in

Area = 289 in

The length of each side of a square is determined by finding the square root of its area. For the first square, the length of its side is √64 = 8inches. For the second square, the length of its side is √225 = 15inches. For the third square, the length of its side is √289 = 17inches.

For a right angle triangle to be formed, Pythagorean theorem must be obeyed. Sum of the square of the smaller sides must equal the square of the longer side. Therefore,

8² + 15² = 17²

289 = 289

Therefore, the correct statement is

Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square

4 0

3 years ago

Answer true or false for 1-10 (picture above)

Softa [21]

$\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a+b}\leq\sqrt{a}+\sqrt{b}\\\\\sqrt{a-b}\geq\sqrt{a}-\sqrt{b}\\----------------------\\1)\ \sqrt{72}=\sqrt{9\cdot8}=\sqrt{9}\cdot\sqrt{8}\qquad TRUE\\\\2)\ \sqrt{13-5}=\sqrt{13}-\sqrt5\qquad FALSE\\\\3)\ \sqrt{9\cdot10}=\sqrt9+\sqrt{10}\qquad FALSE\\\\4)\ \sqrt{18bx}=\sqrt{18}\cdot\sqrt{b}\cdot\sqrt{x}\qquad TRUE\ if\ b\geq0\ and\ x\geq0\\\\5)\ \sqrt{8\cdot12}=\sqrt8\cdot\sqrt{12}\qquad TRUE\\\\6)\ \sqrt{m+x}=\sqrt{m}+\sqrt{x}\qquad FALSE$

$7)\ \sqrt{100+64}=\sqrt{100}+\sqrt{64}\qquad FALSE\\\\8)\ \sqrt{30}=\sqrt{5\cdot6}=\sqrt5\cdot\sqrt6\qquad TRUE\\\\9)\ \sqrt{44}=\sqrt{22+22}=\sqrt{22}+\sqrt{22}\qquad FALSE\\\\10)\ \sqrt{10\cdot10}=\sqrt{10}\cdot\sqrt{10}\qquad TRUE$

3 0

3 years ago

(x7) - 3 = 4

inn [45]

Answer:

detailed one

Please mark as the BRAINLIEST

(ㆁωㆁ)

7 0

2 years ago