In the Figure below is shown the graph of this function. We have the following function:

The
occurs when
, so:

Therefore, the
is the given by the point:

From the figure we have three
:

So, the
occur when
. Thus, proving this:

Answer:
(x+1)^2+(y-7)^2=8
Step-by-step explanation:
You should try the next one and I can check work or tell you if it is right.
The diameter length can be found be computing the distance that (-3,5) is to (1,9) which is sqrt(4^2+4^2)=sqrt(32).
The radius is half the diameter so it is sqrt(32)/2.
The center of the circle is the midpoint of a diameter. So compute the (Average of x, average of y)=(-1,7)
So plug into (x-h)^2+(y-k)^2=r^2 we get
(x+1)^2+(y-7)^2=32/4
simplifying gives
(x+1)^2+(y-7)^2=8
(I had to type this twice; my cat jump on my keyboard)
Answer:
B. 18
Step-by-step explanation:
For the function

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.
1. For 

2. For 

So, limit exists and is equal to 18.
Answer:
a) 26
b) 26/3
Step-by-step explanation:
a)
1) First, you have to turn 4 1/3 into an improper fraction, so you get 13/3
2) Then you do 13/3 *6/1 =78/3 (so you multiply both numerators and denominators)
3) Lastly, 78/3 can be simplified as 26
b)
1) First you turn both fractions into improper fractions, so you get 13/5 and 10/3
2) Then you do 13/5*10/3 (so you multiply both numerators and denominators)
3) You get 130/15, which can be simplified as 26/3