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3 years ago

Find the value of √25-√9/√25+√9

Mathematics

2 answers:

valentina_108 [34]3 years ago

8 0

Answer: 0.25

Step-by-step explanation:

= √25-√9/√25+√9

= 5 - 3 / 5 + 3

= 2 / 8

= 0.25

Rina8888 [55]3 years ago

4 0

Answer:

37/5

Step-by-step explanation:

sqrt(25)=5, sqrt(9)=3 then

sqrt(25)-sqrt(9)/sqrt(25)+sqrt(9)=

5-3/5+3=(5+3)-3/5=8-3/5=40/5-3/5=37/5

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If f(x) = 5x + 4, which of the following is the inverse of (fx)?

lys-0071 [83]

Answer:

see explanation

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 5x + 4 ( subtract 4 from both sides )

y - 4 = 5x ( divide both sides by 5 )

$\frac{y-4}{5}$ = x

Change y back into terms of x

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3 years ago

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

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Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

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Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

$\therefore$ The statement that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ is <em>True.</em>

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Find the value of √25-√9/√25+√9​

Find the value of √25-√9/√25+√9