All categories

3 years ago

What is 1 2/3 times 4/5 in simplest form

Mathematics

1 answer:

Leviafan [203]3 years ago

3 0

Answer:

Step-by-step explanation:

numerator x numerator

denominator x denominator

2 x 4=8

3 x 5=15

1 8/15

You might be interested in

Which pairs of angles in the figure below are vertical angles? Check all that apply.

Furkat [3]

Answer:

A and B

Step-by-step explanation:

Vertical angles are angles that are opposite of each other on two crossing lines.

They have equal angle measure.

When we look at the image, we can tell that, from the given options:

A. <LRA and <FRA and

B. <TRF and <NRL are vertical angles.

5 0

2 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago

The sides of a triangle are 3x+2 6x-1 and 7-x express the perimeter in terms of x

Strike441 [17]

Answer:

x=3

Step-by-step explanation:

3 0

3 years ago

F(r) = 3.14r2. what is f(5)?

rjkz [21]

Answer:

f(5)= 78.5. I hope this helps!!

5 0

3 years ago

During math club, Richard is given four sets of numbers.

ioda

The answer would be C) Set 1 and Set 3. This is because both numbers in the set have to be negative for the statements to be true.

6 0

3 years ago