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2 years ago

10

Are integers real numbers?

1 answer:

Harlamova29_29 [7]2 years ago

6 0

Yes because integers are any numbers, it doesnt matter if its positive or negative

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an elevator is two floors below ground level and goes up 5 floors. write an addition equation that models the location of the el

sveticcg [70]

Below = a negative number (-)
-2
up = positive number
5
the equation would be -2+5 = ?
and the answer/ integer that represents the new location is 3

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2 years ago

yvette has scores of 72 78 66 and 81 on her algebra tests. What score must she make on the final exam in order to pass the cours

sergij07 [2.7K]

72+28+66+81=297
360-297=63
She would need to score 63 on her last exam.

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2 years ago

Select the figure that would be next in the pattern below.

marissa [1.9K]

A because the difference between them is 1 but started at 2 and every time u add an extra 1

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2 years ago

Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°

Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

$\angle OQR+\angle ORQ+\angle ROQ=180^o$

Now, since the figure already shows that angle $m\angle2+\angle ORQ+50^o=180^o$ Now, since we have established that the base angles $m\angle2+m\angle2+50^o=180^o$ we can now solve the above equation for m<2 as follows:

$\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}$

Therefore, the correct answer is: option D

7 0

1 year ago

For your friend's birthday, you have 3 presents to wrap. Find the combined surface area of these 3 gifts so you know how much wr

omeli [17]

The answer is: 5,614 square inches.

The explanation is shown below:

1. The gift on the bottom is a rectangular prism. To calculate its surface area, you must apply the following formula:

$SA=2[(l)(w)+(l)(h)+(h)(w)]$

Where $l$ is the length (20 inches), $w$ is the width (42 inches) and $h$ is the heigth (16 inches).

2. Substitute values:

$SA1=2[(20in)(42in)+(20in)(16in)+(16in)(42in)]=3,664in^{2$

3. The surface area of the other gifts can be calculated with the formula for calculate the surface area of a cube:

$SA=6s^{2}$

Where $s$ is the side.

4. The surface area of the bigger cube is:

$SA2=6(15in^{2})=1,350in^{2}$

5. The surface area of the smaller cube is:

$SA3=6(10in^{2})=600in^{2}$

6. The total surface area (the combined surface area of the three gifts) is:

$SAt=SA1+SA2+SA3\\SAt=3,664in^{2}+1,350in^{2}+600in^{2}\\SAt=5,614in^{2}$

7 0

3 years ago