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laiz [17]
4 years ago
15

Is the number

ddle" class="latex-formula"> rational or irrational
Mathematics
1 answer:
mrs_skeptik [129]4 years ago
4 0

Answer:

Irrational.

Step-by-step explanation:

Rational means that it is a whole number and can be written as a fraction. That doesn't apply for square rooted numbers. So, \sqrt{62} is irrational.

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Do the ratios 12/6 and 2/1 form a proportion?
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6 0
4 years ago
Samira ran 3 more miles than twice the number of miles Ada ran. Which statement makes this comparison using the correct variable
Brilliant_brown [7]
"Samira ran 3 miles more that twice the number of miles Ada ran." This means that to get the number of miles that Samira ran, we will multiply the number of miles that Ada ran and then add 3 to the product.

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Samira ran: 2m + 3 miles

Comparing this to the choices, we will find that the correct choice is the second one:
<span> If Ada ran m miles, then Samira ran 2m + 3 ⁢ miles.</span>
6 0
3 years ago
Read 2 more answers
For <img src="https://tex.z-dn.net/?f=i%3D%20%5Csqrt%7Bx%7D%201" id="TexFormula1" title="i= \sqrt{x} 1" alt="i= \sqrt{x} 1" alig
Sonja [21]
Add the real part and imaginary parts separately:-

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3 0
3 years ago
This is easy but i’m having a bad day and this is almost due please help i will give brainliest
Serjik [45]

Answer:

Step-by-step explanation:

okay so if we lay it out...,

f(x)              6-5x                x-9           x³           2x-5            12x+3

f(-3)              21                   12            -27           -11               -33

f(-2)              16                   -11           -8              -9                -21

f(0)                6                   -9             1                -5                 3

f(1)                 1                    -8             1                -3                 15

f(2)               -4                    -7            8               -1                   27

okay so the left side is all the f(x) values. So the numbers in the "()" represents "x". Now you just substitute the numbers in the"()" for the "x"'s on the top margins. so...,

f(-3)= 6-5x            f(-2)= 6-5x                 f(0)=6-5x               f(1)=6-5x        f(2)=6-5x

f(-3)= 6-5(-3)         f(-2)= 6-5(-2)             f(0)=6-5(0)            f(1)=6-5(1)       f(2)=6-5(2)

f(-3)= 6+15            f(-2)= 6+10                 f(0)=6-0                f(1)=6-5          f(2)=6-10

f(-3)= 21                f(-2)= 16                      f(0)=6                   f(1)= 1              f(2)= -4

f(-3)=x-9               f(-2)=x-9                      f(0)=x-9               f(1)=x-9            f(2)=x-9

f(-3)=(-3)-9            f(-2)=(-2)-9                  f(0)=0-9              f(1)=1-9             f(2)=2-9

f(-3)=-12                f(-2)=-11                       f(0)= -9                f(1)= -8            f(2)= -7

f(-3)=x³                 f(-2)=x³                        f(0)=x³                f(1)= x³              f(2)=x³

f(-3)=(-3)³             f(-2)= (-2)³                    f(0)=0³               f(1)=1³                f(2)=2³

f(-3)= -27             f(-2)= -8                        f(0)= 1                f(1)= 1                 f(2)=8

f(-3)= 2x-5           f(-2)= 2x-5                 f(0)= 2x-5            f(1)= 2x-5      f(2)=2x-5

f(-3)=2(-3)-5         f(-2)=2(-2)-5              f(0)= 2(0)-5          f(1)= 2(1)-5     f(2)=2(2)-5

f(-3)= -6-5            f(-2)= -4-5                  f(0)=0-5               f(1)=2-5         f(2)=4-5

f(-3)= -11               f(-2)= -9                      f(0)= -5                f(1)= -3          f(2)= -1

f(-3)=12x+3            f(-2)=12x+3              f(0)=12x+3          f(1)=12x+3     f(2)=12x+3

f(-3)= 12(-3)+3        f(-2)=12(-2)+3          f(0)=12(0)+3        f(1)=12(1)+3    f(2)=12(2)+3

f(-3)= -36+3          f(-2)= -24+3              f(0)= 0+3             f(1)=12+3       f(2)=24+3

f(-3)= -33                f(-2)= -21                  f(0)=3                 f(1)=15           f(2)= 27

Don't know if you wanted all the work. But I just did it for you so you can see.

7 0
3 years ago
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