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Margarita [4]
3 years ago
7

Am I correct for 2 and 3?

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0

yes. you are correct

Delvig [45]3 years ago
4 0

Yes you are correct congrats

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Note: Images may not be drawn to scale
OleMash [197]

Answer:

  1/3

Step-by-step explanation:

The scale factor is the ratio of image lengths to original lengths. For this pair of figures, the scale factor is ...

  A'B'/AB = 2/6 = 1/3

The scale factor is 1/3.

8 0
2 years ago
HELP!!!!!!!!!! WILL GIVE BRAINLY!!!!!!!
atroni [7]

Answer:

141in^{2}

Step-by-step explanation:

Area of a trapezium = \frac{h}{2}(a + b)

h = height

a and b = upper and and lower lengths

Area of a trapezium = \frac{9}{2}(10 + 16)

 =  \frac{9}{2} × 26

 = 117in^{2}

Area of a triangle = \frac{1}{2} × base × height

 = \frac{1}{2} × 6 × 8

 =  \frac{1}{2} × 48

 = 24in^{2}

Total area = Sum of the areas of both the shapes

 = 117 + 24

 = 141in^{2}

5 0
3 years ago
-5c + 6 = -4 what the first step
ch4aika [34]
Subtract 6 from both sides ( subtract 6 form 6 to get 0 then subtract 6 form -4 to get 2) that’s the first step
7 0
2 years ago
Read 2 more answers
Y=-5/3x + 28/3 in standard form
Temka [501]
3y + 5x - 28 = 0

anything please ask me
7 0
3 years ago
Read 2 more answers
A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in
yanalaym [24]

Answer:

c. 138 feet

Step-by-step explanation:

h(t) = −16t^2 + 83t + 33

At3 seconds

h(3) = -16(3^2) + 83(3) + 33

h(3) = -16(9) + 249 + 33

h(3) = -144 + 249 + 33

h(3) = 138

c. 138 feet

3 0
2 years ago
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