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Montano1993 [528]
4 years ago
11

Subtract 6 from 4 times d

Mathematics
1 answer:
Sindrei [870]4 years ago
4 0

Answer:

2(3 - 2d)

Step-by-step explanation:

All you need to do is factor out 2 from the original expression, so 6 - 4d.

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1. Convert to 0.04, and multiply by 365.

Since I don't want to give the answers, (Some of them I don't understand myself), follow this process for all of the others. For number 2, convert the first exponent equation, and then the second, and multiply both. For number 3, do the same, and then find the average of the product.

Hope this helps, sorry I couldn't be of more help than this.
6 0
3 years ago
Paul's Pizzeria sells 45 cheese pizzas and 20 pepperoni pizzas each week.
Alika [10]

Answer:

45:20

which can be simplified to

9:4


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4 0
3 years ago
Read 2 more answers
Question 18 three consecutive integers have a sum of 42 . find the integers.
Aloiza [94]
The three consecutive integers can be represented by x, x+1, and x+2

x+(x+1)+(x+2)= 42
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Final answer: 13, 14, 15
5 0
3 years ago
How many positive integers between 5 and 31
Anestetic [448]

Answer:

Part (A): There are 9 integers between 5 and 31 which are divisible by 3.

Part (B): There are 6 integers between 5 and 31 which are divisible by 4.

Part (C): There are 2 integers between 5 and 31 which are divisible by 3 and by 4.

Step-by-step explanation:

Consider the provided information.

Part (A) we need to find how many integers between 5 and 31 are divisible by 3.

Between 5 and 31 there are 25 integers.

According to quotient rule: \frac{25}{3} \approx8.33

That means either 8 or 9 integers are divisible by 3 as 8.33 lies between 8 and 9.

The integers are: 6, 9, 12, 15, 18, 21, 24, 27, 30

Hence, there are 9 integers between 5 and 31 which are divisible by 3.

Part (B) we need to find how many integers between 5 and 31  are divisible by 4.

Between 5 and 31 there are 25 integers.

According to quotient rule: \frac{25}{4} \approx6.25

That means either 6 or 7 integers are divisible by 4, as 6.25 lies between 6 and 7.

The integers are: 8, 12, 16, 20, 24, 28

Hence, there are 6 integers between 5 and 31 which are divisible by 4.

Part (C) we need to find how many integers between 5 and 31 are divisible by 3 and by 4

Between 5 and 31 there are 25 integers.

Integers should be divisible by 3 and by 4, that means integers should be divisible by 3×4=12.

According to quotient rule: \frac{25}{12} \approx2.08

That means either 2 or 3 integers are divisible by 3 and by 4 or 12, as 2.08 lies between 2 and 3.

The integers are: 12, 24,

Hence, there are 2 integers between 5 and 31 which are divisible by 3 and by 4.

7 0
3 years ago
Use the distributive property.<br> Simplify the expression below.<br> 5(x - 2) =_-_
olga nikolaevna [1]
<h2>Hey there! </h2><h3>Formula:</h3><h3> \bold{a(b +c)}</h3><h3>\bold{a(b) + a(c)}</h3><h3>\bold{= \ ab + ac}</h3><h3>DISTRIBUTE \bold{5} within the \bold{parentheses}</h3><h3>\bold{5(x -2)}</h3><h3>\bold{5(x) + 5(-2)}</h3><h3>\bold{5(x)=5x}</h3><h3>\bold{5(-2) = -10}</h3><h3>FINALLY: \boxed{\boxed{\bold{Answer: 5x - 10}}}\checkmark</h3><h2>Good luck on your assignment and enjoy your day!</h2>

~\frak{LoveYourselfFirst:)}

7 0
3 years ago
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