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kati45 [8]
3 years ago
8

The perimeter of an equilateral triangle is 6 cm more than the perimeter of a square. The length of a side of the square is 3 cm

less than the length of a side of the equilateral triangle. Find the area of the square.
Mathematics
1 answer:
yan [13]3 years ago
5 0
3t=4s+5          (s=side of square, t= side of triangle)

s=t-3, t=s+3, using this value for t in the first equation gives us:

3(s+3)=4s+5

3s+9=4s+5

-s=-4

s=4

so the side length of the square is 4cm and the area of a square is just s^2

A=16cm^2
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Which of the following describes the transformations of g (x) = negative (2) Superscript x + 4 Baseline minus 2 from the parent
o-na [289]

Answer: First option.

Step-by-step explanation:

Below are some transformations for a function f(x):

1. If f(x)+k, the function is shifted "k" units up.

2 If f(x)-k, the function is shifted "k" units down.

3. If f(x-k), the function is shifted "k" units right.

4. If f(x+k), the function is shifted "k" units left.

5. If -f(x), the function is reflected over the x-axis.

6. If f(-x), the function is reflected over the y-axis.

Then, given the parent function f(x):

f(x)=2^x

And knowing that the the other function is:

g(x)=-2^{(x+4)}-2

You can identify that the function g(x) is obtained by:

- Shifting the function f(x) 4 units left.

-  Reflecting the function  f(x) 4 over the x-axis.

- Shifting the function f(x) 2 units down.

7 0
3 years ago
A teacher is making identical packets using 92 crayons and 23 sheets of paper. What is the greatest number of packets she can ma
Natali [406]
92 crayons
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92÷23=4
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5 0
3 years ago
Read 2 more answers
The sum of two numbers is 14 there diffrence is 6
Alexus [3.1K]

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6 0
4 years ago
Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4
Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

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x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1

line segment PQ  is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1

4 0
4 years ago
Given a mean of 150 and a standard deviation of 25 Define the interval about the mean that contains 95% of the data.
ohaa [14]
By normal curve symmetry 

<span>from normal table </span>
<span>we have z = 1.15 , z = -1.15 </span>

<span>z = (x - mean) / sigma </span>
<span>1.15 = (x - 150) / 25 </span>
<span>x = 178.75 </span>


<span>z = (x - mean) / sigma </span>
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<span>interval is (121.25 , 178.75) </span>

<span>Pr((121.25-150)/25 < x < (178.75-150)/25) </span>
<span>is about 75%</span>
7 0
3 years ago
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