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Nostrana [21]
3 years ago
6

URGENT HURRY ILL MAKE YOU BRAINIEST IF YOU ANWSER. Mae ling earns a weekly salary of $375 plus a 7.5 commission on sales at a gi

ft shop how much would she make in a work week if she sold 4,600 worth of merchandise
Mathematics
1 answer:
sveta [45]3 years ago
7 0

Answer:

I think the answer is 720!

Step-by-step explanation:

You might be interested in
A teacher records the number of students present in her 1st period class each day. This count is a ___________ random variable.
blagie [28]

This count is a discrete random variable (option A).

<h3>What is a discrete random variable?</h3>

A discrete random variable is a variable that contains integers that can only be a limited number of possible values.  A discrete random variable is can contain only a finite set of numbers .

An example of discrete random variable is the number of students in the first period class. It is impossible for the number of students in the class to go on indefinitely.

Discrete random variable has the following properties:

  • It is finite
  • It is numeric
  • It is countable
  • It contains non-negative integers.

A continous random variable is a variable that has an infinite number.

To learn more about discrete data, please check: brainly.com/question/22916429

#SPJ1

7 0
2 years ago
What are the first two answers? #16 and #17
Luden [163]
Answer to number 16 is 27 and 17 is 2
5 0
3 years ago
A car travels 15 miles per gallon of
Arlecino [84]

Answer:

15x = y

Step-by-step explanation:

15 times the gallons of gas =  miles

15x = y

5 0
3 years ago
Power Series Differential equation
KatRina [158]
The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for y

\displaystyle\sum_{n\ge2}\bigg((n-3)(n-2)a_n+(n+3)(n+2)a_{n+3}\bigg)x^{n+1}+2a_2+(6a_0-6a_3)x+(6a_1-12a_4)x^2=0

which indeed gives the recurrence you found,

a_{n+3}=-\dfrac{n-3}{n+3}a_n

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that a_2=0, and substituting this into the recurrence, you find that a_2=a_5=a_8=\cdots=a_{3k-1}=0 for all k\ge1.

Next, the linear term tells you that 6a_0+6a_3=0, or a_3=a_0.

Now, if a_0 is the first term in the sequence, then by the recurrence you have

a_3=a_0
a_6=-\dfrac{3-3}{3+3}a_3=0
a_9=-\dfrac{6-3}{6+3}a_6=0

and so on, such that a_{3k}=0 for all k\ge2.

Finally, the quadratic term gives 6a_1-12a_4=0, or a_4=\dfrac12a_1. Then by the recurrence,

a_4=\dfrac12a_1
a_7=-\dfrac{4-3}{4+3}a_4=\dfrac{(-1)^1}2\dfrac17a_1
a_{10}=-\dfrac{7-3}{7+3}a_7=\dfrac{(-1)^2}2\dfrac4{10\times7}a_1
a_{13}=-\dfrac{10-3}{10+3}a_{10}=\dfrac{(-1)^3}2\dfrac{7\times4}{13\times10\times7}a_1

and so on, such that

a_{3k-2}=\dfrac{a_1}2\displaystyle\prod_{i=1}^{k-2}(-1)^{2i-1}\frac{3i-2}{3i+4}

for all k\ge2.

Now, the solution was proposed to be

y=\displaystyle\sum_{n\ge0}a_nx^n

so the general solution would be

y=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+\cdots
y=a_0(1+x^3)+a_1\left(x+\dfrac12x^4-\dfrac1{14}x^7+\cdots\right)
y=a_0(1+x^3)+a_1\displaystyle\left(x+\sum_{n=2}^\infty\left(\prod_{i=1}^{n-2}(-1)^{2i-1}\frac{3i-2}{3i+4}\right)x^{3n-2}\right)
4 0
3 years ago
A group of 25 people are going to run a race. The top 8 finishers advance to the finals. Determine the number of possible outcom
satela [25.4K]

Answer:

n[total]=25

n[top finishers]=8

the number of possible outcome

=\frac{25 \times 24 \times 23 \times 22 \times 21 \times 20 \times 19 \times 18}{8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}  = 1081575outcomes

6 0
3 years ago
Read 2 more answers
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