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3 years ago

What is the domain of f(x)= 3x/x-1

Mathematics

2 answers:

Tanzania [10]3 years ago

5 0

The answer is all real numbers

domain is easy like that

AURORKA [14]3 years ago

4 0

Answer:

The answer is C on edge (all real numbers except 1)

Step-by-step explanation:

You might be interested in

Drag each label to the correct location on the table. Each label can be used more than once. Match the attributes to the quadrat

nikklg [1K]

9514 1404 393

Answer:

f: x-intercept (-2, 0), y-intercept (0, -8), axis of symmetry x = 1
g: x-intercept (-2, 0), y-intercept (0, 8), minimum value -1
h: axis of symmetry x = 1

Step-by-step explanation:

The equations can be written in factored form and vertex form to see the x-intercepts, axis of symmetry, and extreme value.

The y-intercept is the constant in the equation in standard form.

The axis of symmetry is the vertical line through the vertex.

f(x) = x² -2x -8 = (x -4)(x +2) = (x -1)² -9

x-intercept (-2, 0), y-intercept (0, -8), axis of symmetry x = 1

g(x) = x² +6x +8 = (x +2)(x +4) = (x +3)² -1

x-intercept (-2, 0), y-intercept (0, 8), minimum value -1

h(x) = -x² +2x = -(x)(x -2) = -(x -1)² +1

axis of symmetry x = 1

_____

<em>Additional comment</em>

We have only listed the intercepts, axis, and extreme where the values match a label.

5 0

3 years ago

A linear model of this situation contains the values (15, 300.2) and (26, 177.88) where x represents the number of square inches

maw [93]

Answer: Paula starts with 301.5 yarns.

Step-by-step explanation:

Equation of a line passing through two points (a,b) and (c,d) is given by:-

$(y-b)=\dfrac{b-d}{a-c}(x-a)$

Given: x= number of square inches knitted on the scarf

y= number of yarns remaining on the ball of yarn

The equation of a line passing through (15, 300.2) and (26, 177.88):

$(y-300.2)=\dfrac{26-15}{177.88-300.2}(x-15)\\\\\Rightarrow (y-300.2)=\dfrac{11}{-122.32}(x-15)\\\\\Rightarrow (y-300.2)=\dfrac{11}{-122.32}(x-15)$

To find initial point, put x=0

$y-300.2=-\dfrac{11}{122.32}(0-15)\\\\\Rightarrow\ y-300.2=\dfrac{375}{278}\\\\\Rightarrow\ y=\dfrac{375}{278}+300.2\\\\\Rightatrrow\ y=301.5 \ \ (approx)$

Hence, Paula starts with 301.5 yarns.

5 0

3 years ago

Converting Units Attachment Included

kumpel [21]

100÷11=9.09090909
converting it it will be 9.1 miles per hour

4 0

3 years ago

A town doubles it’s size every 35 years if the population is currently 5,00, what will be the population be in 140 years?

Doss [256]

Answer:

8,000

Step-by-step explanation:

after 35 years 1000

after 70 2000

after 105 4000

qfter 140 8000

i might be wrong but hope this helped there is probs a faster way to do this tho.

5 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0

3 years ago