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saw5 [17]
3 years ago
7

Correct? ...Which quadratic regression equation best fits the data set?

Mathematics
1 answer:
never [62]3 years ago
6 0
1) The second selection looks correct, as it is the only one with a minimum at a positive x value, and a y-intercept more than 109.

2) Your choice cannot be correct, as it corresponds to a function with a minimum near x = 1.278/(2*0.056) ≈ 11.4. The function is obviously decreasing at that point, so is not a minimum there. My calculator shows the 4th selection is best.

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Priscilla bought cheese that weighs ¾ of a pound. If she divides it into portions that are each 1/8 of a pound, how many portion
lakkis [162]

Answer:

6

Step-by-step explanation:

Priscilla bought cheese that weighs ¾ of a pound. If she divides it into portions that are each 1/8 of a pound, how many portions can she make?

¾÷⅛= 6

answer 6

4 0
3 years ago
6-3q < 1 choose all answers that apply
AysviL [449]

Answer:

q>5/3

Step-by-step explanation:

8 0
3 years ago
4. Which of these non-terminating decimals can be converted into a rational number? A. 0.874387438743... B. 0.0000100020003... C
Umnica [9.8K]

Answer: A. 0.874387438743.. is  a rational number.

Step-by-step explanation:

Since Any number that can be written in fraction form is a rational number if it can be in the form of p/q where p and q are integers and q≠0

Since we can write 0.874387438743... = \frac{8743}{9999}

Where, 8743 and 9999 are integers and 9999≠0

Thus, 0.874387438743... is a rational number.

But, 0.0000100020003... ,  5.891420975..... and 10.07401259... can not be written in the form of p/q therefore they are not the rational number.

Therefore, Only Option A is correct.



6 0
3 years ago
Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smalle
aev [14]
Let the smaller number be x.
Let the bigger number be y.

\begin{cases} &4x + 3y = 31 \tex{ ----- (1) } \\ &y- 7 = 2x \tex{ ----- (2) } \end{cases}

Rearrange equation (2):
\begin{cases} &4x + 3y = 31 \tex{ ----- (1) } \\ &y = 2x + 7 \tex{ ----- (2) } \end{cases}



Sub (2) into (1):

4x + 3(2x + 7 ) = 31
4x + 6x + 21 = 31
10x + 21 = 31
10x = 10
x = 1

Sub x = 1 into (2):

y = 2x + 7
y = 2(1) + 7
y= 9

Answer: The two numbers are 1 and 9.

5 0
3 years ago
Read 2 more answers
Juan wants to change the shape of his vegetable garden from a square to a rectangle, but keep the same area so he can grow the s
irina [24]

The value of x that makes sense in this context is; 32.

The dimensions of the new garden is; 64 by 16.

<h3>How to find the real dimensions of the rectangle?</h3>

The expression that represents the problem statement is;

x² = (2x)(x – 16)

Expanding the bracket gives us;

x² = 2x² – 32x

x² - 32x = 0

x(x - 32) = 0

Thus; x = 0 or x = 32

x can't be 0 and as such the value of x is 32.

Thus;

The length of the new garden is; l = 2x = 64.

The width of the new garden is; w = x - 16 = 32 - 16 = 16

The dimensions of the new garden are therefore; 64 by 16

Read more about Rectangle Dimensions at; brainly.com/question/17297081

#SPJ1

4 0
2 years ago
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