Question

Which statement is true about the equation fraction 3 over 4z = fraction 1 over 4z − 3 + 5?

Answer 1

Answer:

It has two solutions.

Step-by-step explanation:

Let as consider the given options are  

It has no solution.

It has one solution.

It has two solutions.

It has infinitely many solutions.

The given equation is

$\dfrac{3}{4z}=\dfrac{1}{4z-3}+5$

Multiply both sides by 4z(4z-3).

$3(4z-3)=4z+5(4z(4z-3))$

$12x-9=4z+80z^2-60z$

$0=-12x+9+80z^2-56z$

$0=80z^2-68z+9$

It is a quadratic equation.

Therefore, it has two solutions.