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lord [1]
3 years ago
11

The population of a bacteria sample doubles every 6 hours. How long would it take for the population to triple?

Mathematics
2 answers:
seraphim [82]3 years ago
8 0

The way to solve this question is to essentially reverse the equation I used in the other answer.


I would solve this with some theoretical values. If you start with 3, how long would it take for it to triple, or reach 9.


the equation would look like 9 = 3(2)^t/6, note how the instead of 1/2 it is now 2 in the parenthesis, as it doubles every 6 hours rather than halves every amount of hours.


When placed into an algebra calculator, the answer should be about 9.5 hours

Flura [38]3 years ago
3 0

Answer is approximently 9.5 HRS. Hope this helps!


Please mark brainliest!

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8 0
3 years ago
Find the sum of the first 17 terms of the arithmetic sequence 10, 14, 18, 22, 26...
kari74 [83]
10, 14, 18 ....

notice, we get the next term by simply adding 4 to the current term, thus "4" is the "common difference, and we know that 10 is the first term.

\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=10\\
d=4\\
n=17
\end{cases}
\\\\\\
a_{17}=10+(17-1)(4)\implies a_{17}=10+(16)(4)
\\\\\\
a_{17}=10+64\implies a_{17}=74\\\\
-------------------------------

\bf \textit{ sum of a finite arithmetic sequence}
\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
a_1=10\\
a_{17}=74\\
n=17
\end{cases}
\\\\\\
S_{17}=\cfrac{17(10+74)}{2}\implies S_{17}=\cfrac{17(84)}{2}\implies S_{17}=714
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3 years ago
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3 years ago
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6 0
3 years ago
Read 2 more answers
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