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oksano4ka [1.4K]
4 years ago
6

Cheyenne is playing a board game. Her score was - 130 at the start of her turn, and at the end of her turn

Mathematics
1 answer:
Svet_ta [14]4 years ago
6 0

Answer: -245

Step-by-step explanation: The reason is because if you add -245 to -130 you will get her present score which is -375.

-245 + (-130)

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Which rate is the lowest price? <br> $6.30 for 9 <br> $5.50 for 5 <br> $4.20 for 7 <br> $0.80 each
Sedbober [7]
Answer: $4.20 for 7
This problem can be solved by dividing the pay by the number of items.

$6.30 / 9 = $0.70
$5.50 / 5 = $1.10
$4.20 / 7 = $0.60
$0.80 / 1 = $0.80

This shows that for the third option, $4.20 for 7, the rate per item is the lowest.
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3 years ago
3.1. Without counting. determine the number of seats in the theatre. Show your working out. on the balcony​
Zinaida [17]

Based on the number of seats on the balcony, the number of seats in the theatre are 600 seats.

<h3>What number of seats does the theatre have?</h3>

The balcony is said to have 120 seats and these are 1/5 of the total seats in the theatre.

The total number of seats in the theatre are:

= Number of seats on balcony / Proportion of seats this represents

Solving gives:

= 120 ÷ 1/5

= 120 ÷ 0.2

= 600 seats

Find out more on ratios and proportions at brainly.com/question/11041750.

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8 0
2 years ago
6. Assume that a component passes a test is 0.85 and that components perform independently. What is the probability that the thi
Tanzania [10]

Answer:

3.90% probability that the third failure will occur on the tenth component tested

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that a component passes a test is 0.85

So they fail with probability of p = 1 - 0.85 = 0.15

What is the probability that the third failure will occur on the tenth component tested

First 9 components: Two failures, that is, P(X = 2) when n = 9.

10th component: Failure with probability 0.15.

So

P = 0.15P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{9,2}.(0.15)^{2}.(0.85)^{7} = 0.2597

So

P = 0.15P(X = 2) = 0.15*0.2597 = 0.0390

3.90% probability that the third failure will occur on the tenth component tested

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3 years ago
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D 2,4,5 it should be ( 3,4,5 )
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