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3 years ago

4th grade math question:

Mathematics

2 answers:

sdas [7]3 years ago

8 0

Answer:

1 gallon

Step-by-step explanation:

gallons of paint needed; 4

gallons used: (3/4)*4

= 1 gallon was used

BARSIC [14]3 years ago

7 0

Answer:

Answer is 3 gallons

Step-by-step explanation:

1 gallon= 25%

2 gallons=50%

3 gallons=75%

3/4 is equivalent to 75%

Hope this helped!

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The following frequency table shows the number of Jui's pictures that have been published in each of the local

MrRa [10]

Answer:2

2Step-by-step explanation:

3 0

4 years ago

Simplify \root(3)(8x^(6))y^(12)

ExtremeBDS [4]

The simplification form of the provided expression is 2x²y⁴ option first is correct.

<h3>What is an expression?</h3>

It is defined as the combination of constants and variables with mathematical operators.

We have an expression:

$= \rm \sqrt[3]{8x^6y^{12}}$

$\rm =\sqrt[3]{8}\sqrt[3]{x^6}\sqrt[3]{y^{12}}$

$\rm \rm = \rm 2\sqrt[3]{x^6}\sqrt[3]{y^{12}}$

$\rm =2x^2\sqrt[3]{y^{12}}$

$\rm =2x^2y^4$

Thus, the simplification form of the provided expression is 2x²y⁴ option first is correct.

Learn more about the expression here:

brainly.com/question/14083225

#SPJ1

4 0

3 years ago

Need some help.

marishachu [46]

Answer:

1, 4, 5

Step-by-step explanation:

rational is when there is an end to the number.

6 0

3 years ago

What is the area of ABC?

Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find $Area \ of \ triangle=\frac{1}{2}base\times height$ ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=2, y_1=1, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}$

find distance between BC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=4, y_1=7, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}$

So, We have height = $\sqrt{20}$ and base = $\sqrt{20}$

Finding area of triangle

$Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10$

So, Area of triangle ABC = 10

Option C is correct.

7 0

3 years ago

The product of some negative number and 4 less than twice that number is 286 find the number

Naya [18.7K]

Let's say that number is hmmm "a"

now.. twice "a" is 2*a or 2a
4 less than that is " 2a - 4"

now, the product of those two fellows is 286, well ok

a( 2a - 4) = 286

thus

$\bf a(2a-4)=286\implies 2a^2-4a^2=286\implies a^2-2a^2=143
\\\\\\
a^2-2a^2-143=0\implies (a-13)(a+11)=0
\\\\\\
\begin{cases}
a-13=0\implies &a=13\\
a+11=0\implies &\boxed{a=-11}
\end{cases}$

5 0

4 years ago