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Anon25 [30]
3 years ago
6

35 61 63 69 49 46 52 32 34 50 WHAT IS THE MEAN

Mathematics
2 answers:
NemiM [27]3 years ago
5 0

Answer:

49.1

Step-by-step explanation:

First add up all the numbers

35 + 61 = 96 + 63 = 159 + 69 = 228 + 49 = 277 + 46 = 323 + 52 = 375 + 32 = 407 +34 = 441 + 50 = 491

after you added all the numbers divide by amount of numbers

491/10 = 49.1

ad-work [718]3 years ago
3 0

Answer:

49.1

Step-by-step explanation:

Add all the numbers up together and divide by how many there are so....

35 + 61 + 63 + 69 + 49 + 46 + 52 + 32 + 34 + 50 = 491

491 divided by 10 is 49.1

hope this helps!

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Integrate 1 - x / x(x2 + 1) d x by partial fractions.
solniwko [45]

Answer:

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

Step-by-step explanation:

step 1:-   by using partial fractions

[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }......(1)

<u>step 2:-</u>

solving on both sides

1-x=A(x^{2} +1)+(Bx+C)x......(2)

substitute x =0 value in equation (2)

1=A(1)+0

<u>A=1</u>

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1  =  C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now  

\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 }  d x -\int\limits \frac{1}{x^{2}+1 }  d x

by using integration formulas

i)  by using \int\limits \frac{1}{x}   d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\.....(b)

\int\limits tan^{-1}x  dx =\frac{1}{1+x^{2} } +C.....(c)

<u>step 4:-</u>

by using above integration formulas (a,b,and c)

we get answer is

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

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