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Sergeeva-Olga [200]
3 years ago
5

Thanks to who ever helped me with this question!​

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0

Answer:

61

Step-by-step explanation:

a triangles angles equal 180 so 180-10-19-90 = 61

ollegr [7]3 years ago
3 0

Answer:

-9

Step-by-step explanation:

Since the opposite angles of both sides are congruent we know that the sides must be congruent also. Therefore, to solve for x we can set them equal to each other.

So the equation will be x+19=10, to solve we must isolate the variable.

First, subtract 19 from both sides

x+19-19=10-19

Then, simplify

x=-9

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In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD
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Answer:

The area of   parallelogram ABCD  is78.42 \mathrm{in}^{2}

Explanation:

Given:

AD = 12 in

m \angle C=46^{\circ}

m \angle D B A=72^{\circ}

To Find:

The area of   parallelogram ABCD=?  

Solution:

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The area of the parallelogram can be calculated by a b * \sin (a n g l e)

Substituting the value of a=12  we have

\text { Area of parallelogram }=12 * \text { bsin } 46

<u>To find  the value of b, </u>

We know that area of a triangle can be expressed as,

\text { Area of triangle }=(A b / 2) \sin (\text {angle})

So,

(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72

Cancelling BD and 2 on both sides we get,  

12 * \sin 46=A B * \sin 72

A B=12 * \frac{\sin 46}{\sin 72}

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Work out m and c for the line: 3 y + 6 x = − 3
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Answer:

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Step-by-step explanation:

• Let's first phrase out the general equation of a line

{ \rm{y = mx + c}}

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[ remember that a general line equation must be in slope - intercept form as shown above ]

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→ <em>r</em><em>e</em><em>m</em><em>e</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>a</em><em>p</em><em>p</em><em>l</em><em>y</em><em> </em><em>"</em><em>s</em><em>u</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>m</em><em>a</em><em>k</em><em>i</em><em>n</em><em>g</em><em> </em><em>k</em><em>n</em><em>o</em><em>w</em><em>l</em><em>e</em><em>d</em><em>g</em><em>e</em><em>"</em>

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