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3 years ago

find the perimeter and diagonal of a square whose area is equal to the area of a rectangle whose length is 9m and breadth is 4m

1 answer:

4 0

$Area\ of\ a\ rectangle:A_{\fbox{ }}=9m\times4m=36m^2\\\\a-side\ of\ a\ square\\\\Area\ of\ a\ square:A_{\fbox{}}=a^2\\\\A_{\fbox{ }}=A_{\fbox{}}\Rightarrow a^2=36m^2\Rightarrow a=\sqrt{36m^2}\Rightarrow a=6m\\\\Perimeter\ of\ the\ square:P=4a\Rightarrow P=4\times6m=\boxed{24m}\\\\Diagonal\ of\ the\ square:d=a\sqrt2\Rightarrow d=\boxed{6\sqrt2\ m}$

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Solve each equation. 7) 18 =-2+a 8) -7= m - 12 9) -8(7 + 7n)=-336 10) -140=-7(-4+36)

lesya692 [45]

Answer:

7) a= 20

8) m= 5

9)n = 5

10) b = 8

Step-by-step explanation:

7) 18+2=-2+2+a

>> 20 = a >> a = 20

18 + 2 = 20 so that isolates the variable leaving a = 20

8) -7+12 = m -12+12

>>> 5 = m >> m = 5

-7 + 12 = 5 so that again isolates the variable leaving m = 5

9) -8(7 + 7n) = -336

>> -56+56 + -56n = -336+56

>>> -56n/-56 = -280/-56

>>>> n = 5

use distributive property, cancel out necessary numbers, isolate the variable. leaving n = 5.

10) -140 = -7(-4 + 3b)

>> -140 = 28 - 21b >> -140-28 = -21b +28-28 ( flipped the numbers)

>>> -168/-21 = -21b /-21

>>>> 8 = b >> b =8

Hope it helps!

5 0

3 years ago

Can someone check my work?. 1. Simplify the given expression.. (7 − 3i) • (2 − i) . 4 + i (MY ANSWER) . . 14 + 3i . . 11 − 13i .

Annette [7]

1. (7 − 3i) • (2 − i)
It is simplified as follows:
14 - 7i -6i - 3
11 - 13i

2. (−5 + 3i) • (1 − 2i)
It is simplified as follows:
-5 + 10i + 3i + 6
1 + 13i

3. (1 + 3i) + (2 − 5i)
It is simplified as follows:
1 + 3i + 2 − 5i
3 - 2i

4. (6 + 2i) − (8 − 3i)
It is simplified as follows:
6 + 2i − 8 + 3i
-2 + 5i

4 0

3 years ago

I'm being timed pls help will pick brainliest

stiv31 [10]

Answer:

Cos 0° = 6.42 = V1

6th quadrant.

So, cos x = 0 implies x = (2n + 1)π/2 , where n takes the value of any integer. For a triangle, ABC having the sides a, b, and c opposite the angles A, B, and C, the cosine law is defined. In the same way, we can derive other values of cos degrees like 30°, 45°, 60°, 90°, 180°, 270°and 360

Step-by-step explanation:

if sin a= 3/4 then a = 50

if sin = 4/5 then a = 60

if sin = 2/3 then a = 40

But we can perfect this

if sin = 4/5 then a = 57 as 4/5 = 0.83

We want 0.8 = 4/5

if sin = 4/5 then a = 54 as 4/5 = 0.809

if sin = 4/5 then a = 53.5 as 4/5 = 0.80385

Now for cos

It is much easier than it initially appears. Remember the definition of SINE:

SINΘ = opp In your case, that means the opposite is 4/5 = 0.80385 (yes, ignore the sign for now) and the hypotenuse is 11.48910018

hyp Please draw that triangle right now, because it will help you a lot at the end.

53.50 degree Remember to place the angle in the appropriate spot.

Now, use the Pythagorean Theorem to find the missing side (easy, right? It's 9.534) and place it in the adjacent position.

You can easily find all of the trig functions now!

Simply remember that:

COSΘ = Adj with SEC the reciprocal of this one

Hyp

TANΘ = Opp COT the reciprocal of TAN and, if anyone asks, CSC coming from SIN.

Adj

I told you to ignore the signs, but now we can't anymore. Remember the four quadrants and the memory trick:

A -- ALL are positive

Smart -- SIN and CSC are positive

Trig -- TAN & COT are positive

Class -- COS and SEC are positive.

Since your SIN was negative, it must be in III or 6, and COS is positive in I and 6 So we're in quadrant 6 then!

Only your COS and SEC will be positive, the rest negative

7 0

3 years ago

7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con

sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let $p_{1}$ be the probability that commercial cars have rear license plates and $p_{2}$ be the probability that connected trucks have rear license plates.

Cars Trucks Total

Total 2049 334 2383

x 239 45 284

p 0.1166 0.1347 0.1191

α=0.05

Hypothesis will be :

$H_{0}:p_{1} =p_{2}$

$H_{1} :p_{1} < p_{2}$

It is a left tailed test at 0.05 significance.

Standard errors of p= $\sqrt{p(1-p)/n}$

= $\sqrt{(0.1191*0.8809)/2383}$

= $\sqrt{0.1049/2383}$

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0

2 years ago

4w+2=2w+7 Please quick I dont have time!

Studentka2010 [4]

That’s the answer for this problem

4 0

3 years ago

Read 2 more answers