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sergejj [24]
3 years ago
9

Does anyone know this??

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer: 21

Step-by-step explanation: To solve this problem, we can first set up a proportion because we know that 3 is to 7 as 9 is to x.

So we have \frac{3}{7} = \frac{9}{x}.

Now, we can use cross products to find the missing value.

So we have 3 time x which is 3x and 7 times 9 which is 63.

Rewriting our equation, we have 3x = 63.

Dividing both sides by 3, we find that <em>x = 21</em>.

So, <em>x = 21</em>.

The red arrows in the middle mean that they are parallel so the slopes are the same.

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The value of my hundred digit is 300, the value of my tens digit is zero. The value of my ones digit is an even number greater t
rusak2 [61]

Answer:

308 would be the number you are looking for.

Step-by-step explanation:

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3 years ago
Screenshoted question below
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Answer:

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Step-by-step explanation:

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(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

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3 0
3 years ago
Read 2 more answers
A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590
Jet001 [13]

Let's assume

height of plane  in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

y-y_1=m(x-x_1)

points as

(5,6500)

x1=5, y1=6500

(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug values

m=\frac{5900-6500}{7-5}

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Equation of line:

we can use formula

y-y_1=m(x-x_1)

we can plug values

h-6500=-300(t-5)

h=-300t+8000

Time of landing:

we can set h=0

and then we can solve for t

h=-300t+8000=0

t=\frac{80}{3}min..............Answer

5 0
4 years ago
A 3-kilogram bag of carrots costs $2.71. What is the unit price, rounded to the nearest cent?
MissTica

Answer:

The unit price is $0.90.

Step-by-step explanation:

$2.71 divided by 3 = 0.9033333333333.

Rounded equals: $0.90.

4 0
3 years ago
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