All categories

1 year ago

Consider the expressions 7y + 5 − 3 and 7y + 2. Which statement is true?

Mathematics

1 answer:

romanna [79]1 year ago

4 0

The two expressions are equivalent because they have the same value regardless of the number of substituted in for y

You might be interested in

The legs of a isosceles triangle are 0.3 foot less then twice the base . The perimeter of the triangle is 4.9 feet .

kicyunya [14]

<h2>Greetings!</h2>

Answer:

The legs are 1.9 feet long

And the base is 1.1 feet long.

Step-by-step explanation:

Firstly, you need to find the value of x.

You need to add all the sides together:

2x - 0.3 + 2x - 0.3 + x

Simplified =

5x - 0.6

And this equals 4.9:

5x - 0.6 = 4.9

Next, you need to move the -0.6 over to the other side, making sure to make it a positive:

5x = 4.9 + 0.6

5x = 5.5

Now divide each side by 5:

$\frac{5x}{5} = \frac{5.5}{5}$

x = 1.1

As the image is unclear of what side you are finding the length of:

2x - 0.3 = 1.9 feet long

And the base is 1.1 feet long.

<h2>Hope this helps!</h2>

4 0

3 years ago

Read 2 more answers

What is sin(A)?<br> 13<br> 12<br> A<br> 5<br> sin(A) =

eimsori [14]

Answer:

sin A = 12/13

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opposite side/ hypotenuse

sin A = 12/13

6 0

2 years ago

: A sports store sells a total of 70 soccer balls in one month, and collects a total of $2,400. A limited Edition soccer ball is

sweet-ann [11.9K]

Answer:

The store sold 43 pro NSL soccer balls.

The store sold 27 limited Edition soccer balls.

Step-by-step explanation:

Let x represent number of limited Edition soccer balls and y represent the number of pro NSL soccer balls.

We have been given that a sports store sells a total of 70 soccer balls in one month. We can represent this information in an equation as:

$x+y=70...(1)$

Cost of x limited Edition soccer balls: $65x$

Cost of y pro NSL soccer balls: $15x$

We are also told that store collected a total of $2,400. We can represent this information in an equation as:

$65x+15y=2400...(2)$

From equation (1), we will get:

$x=70-y$

Substituting this value in equation (2), we will get:

$65(70-y)+15y=2400$

$4550-65y+15y=2400$

$4550-50y=2400$

$4550-4550-50y=2400-4550$

$-50y=-2150$

$\frac{-50y}{-50}=\frac{-2150}{-50}$

$y=43$

Therefore, the store sold 43 pro NSL soccer balls.

Now, we will substitute $y=43$ in equation (1) to solve for x:

$x+43=70$

$x+43-43=70-43$

[tex]x=27/tex]

Therefore, the store sold 27 limited Edition soccer balls.

4 0

3 years ago

A polynomial of degree 3 has a double zero at 2. When x = 1 it takes the value 6 and when x = 3 it

masha68 [24]

Answer:

p(x)=(x-2)^2(x+5)

Step-by-step explanation:

p(2)=0 then p(x) =(x-2)^2(x-x1), x1=?

p(1)=6

p(3)=8

p(1)=(1-2)^2(1-x1)

6= (-1)^2 (1-x1)

6=1(1-x1)

6=1-x1

x1=-5;

then p(x) =(x-2)^2(x-(-5))=(x-2)^2(x+5)

Really: f(3)=(3-2)^2(3+5)=1*8=8

3 0

3 years ago

What are the solutions to x^2-13x+30

BlackZzzverrR [31]

$ax^2+bx+c=0 \\ \\
x^2-13x+30 = 0 \\ \\ D=b^2-4ac = 169-120=\sqrt{49} =7 \\ \\ x_{1/2} = \frac{-b^2+/-\sqrt{D}}{2a} = \frac{13+/-7}{2*1} \\ \\ x_1 = \frac{13+7}{2} = 10 \\ \\ x_2 = \frac{13-7}{2} = 3$

4 0

3 years ago