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disa [49]
3 years ago
11

Solve the equation using the quadratic formula. Enter each solution in simplest form.

Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

For this case we have the following quadratic equation:

x ^ 2-4x + 23 = 0

The solutions will be given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Where:

a = 1\\b = -4\\c = 23

Substituting the values we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}

We have two roots:

x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}

ANswer:

x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}

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BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°, what is the value of m?
krok68 [10]

Answer:

The correct answer is option B.  17

Step-by-step explanation:

It is given that, ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°

<u>To find the value of m</u>

From the figure we can see that, triangle WYZ is an isosceles  triangle.

ZW = ZY

Then <YXZ = <WXZ = 90°

It is given ∠YXZ  = (6m – 12)°

(6m – 12)° =  90°

6m = 90 + 12  = 102

m = 102/6 = 17

Therefore the value of m = 17

The correct answer is option B.  17

8 0
3 years ago
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Can someone please help me
lisov135 [29]

Answer:

5.83 or E

Step-by-step explanation:

Use Pythagorean theorem. 5^2+3^2=c^2 because the diameter is perpendicular it cuts the chord in half.

25+9=c^2  

34=c^2

5.83

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Help please <br><br>number 4, 5, 6, and 7​
FinnZ [79.3K]

Step-by-step explanation:

4. So, total time traveled is calculated by adding travel times in both directions.

From Detroit to Chicago, Charlie flew 300 miles at 150 miles per hour speed. That means that he traveled:

t1 = s / v1

t1 = 300 miles / 150 miles per hour

t1 = 2 hours

Now, let's do the same for the opposite direction. Since it's the same distance, he again flew 300 miles, but the speed this time was 100 miles per hour:

t2 = s / v2

t2 = 300 miles / 100 miles per hour

t2 = 3 hours

So, total time he traveled was t1 + t2 = 2 hours + 3 hours = 5 hours.

For the trip distance we need to add distances in both directions. We already said that the distance is the same, so the total trip distance is 300 miles + 300 miles = 600 miles.

Displacement shows how far are the ending and the starting point. Since Charlie started from Detroit, flew to Chicago, and then came back to Detroit, his ending point is the same as the starting, so the displacement is 0.

We can calculate average speed by dividing total distance with the total travel time. We already found that the total trip distance was 600 miles, and the total travel time was 5 hours. That means that:

v(average) = s(total) / t (total)

v(average) = 600 miles / 5 hours

v (average) = 120 miles per hour

As for the average velocity, we calculate it by dividing displacement by total travel time. Since the displacement was 0, average velocity will also be 0.

5. From the left graph we see that the object went from 0 to 2 meters (it moved 2 meters) in 1 second. That means that its speed was:

v1 = s1 / t1

v1 = 2 meters / 1 second

v1 = 2m/s

From there, it went from 2 to 4 meters (it moved 2 meters) in the next 4 seconds. That means that its speed, during that interval, was:

v2 = s2 / t2

v2 = 2 meters / 4 seconds

v2 = 0.5 m/s

So, our graph will show, for the first second, velocity of 2m/s, and for the next four seconds, the velocity of 0.5 m/s.

6. Again, when calculating speed, we use the equation:

v = s / t

In this case, the distance (s) is 325 miles and the time (t) is 5 hours. So, the speed will be:

v = 325 miles / 5 hours

v = 65 mph

7. Now, we have the same distance (s) of 325 miles ant the speed (v) of 70 mph. We want know how long will the drive take:

t = s / v

t = 325 miles / 70 mph

t = 4.64 hours.

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3 years ago
Complete the Punnett square below and choose the probability of the offspring.
saul85 [17]

Answer:

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Step-by-step explanation:

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