Answer:
Area of the rectangular Field = 3 8/9 km²
Step-by-step explanation:
Length of the field = 2 1/3 km
Width of the field = 1 2/3 km
Area of a rectangular Field = length × width
= 2 1/3 × 1 2/3
= 7/3 × 5/3
= (7*5)/(3*3)
= 35/9
Area of the rectangular Field = 3 8/9 km²
Perimeter of the rectangular Field = 2(length + width)
= 2(2 1/3 + 1 2/3)
= 2(7/3 + 5/3)
= 2(7+5/3)
= 2(12/3)
=2(4)
= 8 km
Perimeter of the rectangular Field = 8 km
Answer:
At 25 = 6.8612mm
At 50 years = 5.422mm
Step-by-step explanation:
Equation,
d = 2.115Logₑa + 13.669
d = diameter of the pupil
a = number of years
Note : Logₑa = In a (check logarithmic rule)
d = 2.115Ina + 13.669
1. At 25 years,
d = -2.115In25 + 13.669
d = -2.115 × 3.2188 + 13.669
d = -6.807762 + 13.669
d = 6.8612mm
At 25 years, the pupil shrinks by 6.86mm
2. At 50 years,
d = -2.1158In50 + 13.669
d = -2.1158 * 3.912 + 13.669
d = -8.2770 + 13.699
d = 5.422mm
At 50 years, the pupil shirks by 5.422mm
To save this question, I had to plug in the values into the equation.
Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.
Answer:
5(x+3)
Step-by-step explanation:
:)
I can’t tell what i’m solving for? factor? graph? slope?