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kotegsom [21]
3 years ago
9

In Sakura's garden, for every 5 red flowers, there are 10 yellow flowers. There are a total of 75 yellow and red flowers in her

garden. How many red flowers are in Sakura's garden?
Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:

25 red flowers

50 yellow flowers

Step-by-step explanation:

We can determine the ration of red flowers to yellow flowers is 5:10 which 1:2. Therefore every red flower there is 2 yellow flowers in the garden. If there is a total of 75 yellow and red flowers in the garden, we can calculate the number of yellow and red flowers because we know the ratio.

we can determine the percentage of yellow to red flowers:

If the possibility is 15 flowers, with five red flowers and 10 yellow flowers:

5/15=1/3

10/15=2/3

Therefore the amount of red flowers are:

(1/3)\cdot{75}=75/3=25

The amount of yellow flowers are:

=75-25=50

There is 25 red flowers and 50 yellow flowers in the garden

Katarina [22]3 years ago
3 0

Answer:

25

Step-by-step explanation: Understand it as a ratio. 5:10. Add both ratios together, 15. Make an expression, 15x=75. x=5, Then multiply 10 and 5 by 5 and that will give you the ratio of 25:50 red to yellow flowers.

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Answer:

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In question 1 the answer is "Option b".

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Step-by-step explanation:

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5 0
3 years ago
Darwin's best time for running 5000 metres is 16 minutes. He wants to run it in 15 minutes and 30 seconds.
Rudik [331]

Answer:

3 percent

Step-by-step explanation:

convert to seconds

960 seconds to 930 seconds

30 seconds ÷ 960=3 per cent

6 0
2 years ago
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In the given figure a + b + c = 295° , fins the value of a , b , c and d....​
Contact [7]

Answer:

a and c = 115 and b and d = 65

Step-by-step explanation:

Hope this helps :)

5 0
2 years ago
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There are 22 rows of seats on a concert hall: 23 seats are in the 1st row, 27 seats on the 2nd row, 31 seats on the 3rd row, and
JulijaS [17]
We can model this situation with an arithmetic series.
we have to find the number of all the seats, so we need to sum up the number of seats in all of the 22 rows.

1st row: 23
2nd row: 27
3rd row: 31
Notice how we are adding 4 each time.

So we have an arithmetic series with a first term of 23 and a common difference of 4.

We need to find the total number of seats. To do this, we use the formula for the sum of an arithmetic series (first n terms):

Sₙ = (n/2)(t₁ + tₙ)

where n is the term numbers, t₁ is the first term, tₙ is the nth term

We want to sum up to 22 terms, so we need to find the 22nd term

Formula for general term of an arithmetic sequence:

tₙ = t₁ + (n-1)d,

where t1 is the first term, n is the term number, d is the common difference. Since first term is 23 and common difference is 4, the general term for this situation is

tₙ = 23 + (n-1)(4)

The 22nd term, which is the 22nd row, is

t₂₂ = 23 + (22-1)(4) = 107

There are 107 seats in the 22nd row.

So we use the sum formula to find the total number of seats:

S₂₂ = (22/2)(23 + 107) = 1430 seats

Total of 1430 seats.
If all the seats are taken, then the total sale profit is

1430 * $29.99 = $42885.70
4 0
3 years ago
A cylinder has radius r and height h. A. How many times greater is the surface area of a cylinder when both dimensions are multi
Ierofanga [76]

Answer: A. Factor 2 => 4x greater

                   Factor 3 => 9x greater

                   Factor 5 => 25x greater

Step-by-step explanation: A. A cylinder is formed by 2 circles and a rectangle in the middle. That's why surface area is given by circumference of a circle, which is the length of the rectangle times height of the rectangle, i.e.:

A = 2.π.r.h

A cylinder of radius r and height h has area:

A_{1} = 2πrh

If multiply both dimensions <u>by a factor of 2</u>:

A_{2} = 2.π.2r.2h

A_{2} = 8πrh

Comparing A_{1} to A_{2} :

\frac{A_{2}}{A_{1}} = \frac{8.\pi.rh}{2.\pi.rh} = 4

Doubling radius and height creates a surface area of a cylinder 4 times greater.

<u>By factor 3:</u>

A_{3} = 2.\pi.3r.3h

A_{3} = 18.\pi.r.h

Comparing areas:

\frac{A_{3}}{A_{1}} = \frac{18.\pi.r.h}{2.\pi.r.h} = 9

Multiplying by 3, gives an area 9 times bigger.

<u>By factor 5</u>:

A_{5} = 2.\pi.5r.5h

A_{5} = 50.\pi.r.h

Comparing:

\frac{A_{5}}{A_{1}} = \frac{50.\pi.r.h}{2.\pi.r.h} = 25

The new area is 25 times greater.

B. By analysing how many times greater and the factor that the dimensions are multiplied, you can notice the increase in area is factor². For example, when multiplied by a factor of 2, the new area is 4 times greater.

3 0
3 years ago
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