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brilliants [131]
3 years ago
11

Find the greatest common factor of 17 and 25

Mathematics
2 answers:
Ann [662]3 years ago
6 0

Answer:

1

Step-by-step explanation:

A common factor is a number such that both 17 and 25 are divisible by that number. In this case, the greatest common factor of 17 and 25 is 1.

mixas84 [53]3 years ago
6 0

Answer: 1

Step-by-step explanation:

The only common factor between 17 & 25 is 1. That makes 1 Greatest common factor.

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Find the five-number summary for the given data. Min Q1 Q2 Q3 Max
Aleonysh [2.5K]

Answer with Step-by-step explanation:

16 19 21 26 27 29 34 35 35 39 40 41 42 50 50 52 57 60 75 76 78 81 84

the data is already arranged in ascending order

Min=16

Max=84

The quartiles for the odd set of data is given by

Qi=\dfrac{i(n+1)}{4}\ th\ term

where n is the number of elements

Here, n=23

Q1=\dfrac{(23+1)}{4}\ th\ term

Q1=6 th term

Q1=29

Q2=12 th term

Q2=41

Q3=18 th term

Q3=60

Hence, five-number summary for the given data is:

Min  Q1   Q2   Q3   Max

16     29   41     60    84

8 0
3 years ago
I need help completing this answer are you available
melomori [17]

Answer:

Step-by-step explanation:

7 0
3 years ago
Dan earns £224 over the course of a five-day week. How much is that per day?
alina1380 [7]

224/5= 44.8

He enrns 44.8 per day

4 0
3 years ago
What is 15% of 60? create a model to prove your answer. in equivalent fractions
amid [387]
15% of the number 60 is 9
6 0
3 years ago
Simon drove through some roadworks where the speed limit was 50 mph. Two cameras recorded the time taken to travel 1200 m throug
Tom [10]

Answer:

Speed = 21.43m/s

Step-by-step explanation:

Given

Distance = 1200m -- of the roadworks

Time\ Recorded = 56s

Required

Determine the speed

In this case:

Speed = \frac{Distance\ of\ Roadword}{Time\ Captured}

Speed = \frac{1200m}{56s}

<em></em>Speed = 21.43m/s<em> --- approximated</em>

3 0
3 years ago
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