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2 years ago

What information do you get from a bar graph

Mathematics

2 answers:

liq [111]2 years ago

8 0

Bar graphs are used to handle data and they are similar to a line graph
hope this helps :)

Step2247 [10]2 years ago

7 0

Numbers shade ins and lines

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If x = y, find the value of 8 + 5(x - y)

uranmaximum [27]

Answer:

Step-by-step explanation:

Evaluate for x=y,y=x

8+5(x−x)

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2 years ago

Which pair of triangles is congruent?

stiv31 [10]

Answer:

The first pair.

Step-by-step explanation:

3 corresponding parts must be congruent for two triangles to be congruent. The first pair has 3 congruence markings; two angles and one side are congruent. Additionally, they are congruent by the ASA postulate because two angles and the included side are congruent.

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2 years ago

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Answer--->x/3<br>Process?

Komok [63]

Step-by-step explanation:

2x/3 - x/3 = x/3

they both have the same denominators (number at the bottom of the fraction) so all you have to do it subtract the numerators (top of the fraction) together. 2x-x =x, that's why it's x on the numerator for the answer

hope this helps

4 0

2 years ago

Read 2 more answers

Jane and Sali cycled along the same 63km route. Jane took 3.5 hours to cycle the 63km.

Arisa [49]

Answer:

sali's speed was 18.75 km/h

Step-by-step explanation:

Jane took 3.5 hours to cycle the 63 km.

As, , so the speed of Jane will be:

Suppose, the speed of Sali is km/h

Sali caught up with Jane when they had both cycled 30 km.

So, the time required for Jane to cycle 30 km and the time required for Sali to cycle 30 km

Given that, Sali started to cycle 4 minutes or after Jane started to cycle. So, the equation will be.......

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3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago