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son4ous [18]
3 years ago
15

Help me on #6 please and quickly please

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0
Hey there!

To start, you have one of your angles given, 40.5.  Now, given that the airplane is directly over point A of the triangle, you can conclude that ∠A is 90 degrees.

Knowing that the sum of all the angles of a triangle is 180 degrees, to find ∠P, you can set up this equation (where x is the missing angle of ∠P):
40.5+90+x=180

Simplify and solve for x:
40.5+90+x=180
130.5+x=180
x=49.5

Therefore, m∠P is equal to 49.5 degrees.

Hope this helps and have a marvelous day!

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jok3333 [9.3K]

Answer: #1 is 10. #2 is 24. #3 is 3 1/5. #4 is 1 1/9. #5 is 21. #6 is 10 2/3. #7 is 30. #8 is 11 3/7. I’m only telling you eight of them because you are in fifth grade and you should try to complete the worksheet even if you mess up. You will learn from your mistakes after the paper is graded.


Step-by-step explanation: To get the answer, all you have to do is flip the second number and then multiply.


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3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

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W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

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Let x be a real number. Find the lowest possible value of |5x^2 - 16| + |10x - 2|.
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Answer:2

Step-by-step explanation:

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