Negative 1 over 11
negative 1 over 30
1 over 30
1 over 11
-1/6*-1/5 = 1/30
Answer:
80
Step-by-step explanation:
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
3w +2 =7w
-3w -3w
2=4w
Divide each side by 4
1/2=w
Check your answer:
3 (1/2) + 2 = 7 (1/2)
(3/2) + (4/2) = (7/2)
(7/2) = (7/2)
Hope this helps.
No because adding the two fives will give you a 10 and 10 is greater than 3
