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mestny [16]
3 years ago
5

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

by dollar 3. find the original duration of the tour. (Hint use quadratic equation)
Mathematics
1 answer:
Greeley [361]3 years ago
4 0

Answer:

The original duration of the tour  is 18 days.

Step-by-step explanation:

Let

the number of days spent be T

Daily expenses be D

Initially ,

total tour expenses was 360

D \times T=360

D = \frac{360}{T}-------------(1)

If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3

(D + 4) \cdot(T -3) = 360---------------(2)

Expanding the eqaution(2)

DT-3D + 4T -12 = 360

Substituting the value of D

(\frac{360}{T})T -3( \frac{360}{T}) + 4T -12 = 360

(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 360 + 12

(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 372

360 - ( \frac{1080}{T}) + 4T= 372

( \frac{1080}{T}) + 4T= 372 - 360

( \frac{1080}{T}) + 4T= 12

1080 + 4T^2= 12T

Solving the quadratic equation we get

T = 18  and T = -15

T is the number of gays and it cannot be negative , hence T is 18

Substituting in equation (1) we get

D = \frac{360}{18}

D =  20

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