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2 years ago

In a bag, there are 5 red marbles, 2 blue marbles, and 3 purple marbles. What is the probability of drawing a purple marble?

Mathematics

1 answer:

Kitty [74]2 years ago

7 0

Answer:

3/10 or 30%

Step-by-step explanation:

Add all of the marbles: 5+2+3=10

Then use a fraction to represent the three purple marbles: 3/10

That porportion is your answer

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Explain why the function is discontinuous at the given number

Novosadov [1.4K]

Answer:

left limit = 2 ≠ 1/2 = right limit

Step-by-step explanation:

A function is discontinuous if the limit of the function value approaching the point from the left is different than the limit approaching from the right.

Here, the left limit is 2 and the right limit is 1/2. The limits are different, which is why the function is discontinuous at x=-1.

7 0

3 years ago

Nichole bought a gift for her friend. She

OlgaM077 [116]

Answer:

10 by 5 =50

10 by 5=50

10 by 2=20

2 by 5=10

100+40+20=160

3 0

3 years ago

On december 1, jonas jewelry wholesale center started with an inventory of 1,000 watches. shipments of 168, 231, and 411 were se

denis-greek [22]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Total watches in an inventory = 1000

Number of shipments sent out = 168, 231, 411

So, Remaining inventory of watches would be :

$1000-(168+231+411)\\\\=1000-810\\\\=190$

New receipts = 21, 145 and 11

So, Number of watches on hand becomes :

$190+(21+145+11)\\\\=367$

Hence, Third option is correct.

5 0

3 years ago

Mario brought a 1 gallon can of paint to paint his room. He used 0.5 gal for the fist coat and 0.4 gal for the second coat. How

emmainna [20.7K]

It would be 1/10 OR 0.1

7 0

3 years ago

Read 2 more answers

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

3 years ago