Solve. Log2 (8x) - Log2 (x^2-1) = Log2 3
1 answer:
<h3>Answer:</h3>
x = 3
<h3>Step-by-step explanation:</h3>Taking the antilog, the equation becomes ...
... 8x/(x^2 -1) = 3
Multiplying by the denominator, you have ...
... 8x = 3(x^2 -1)
Subtracting the left side to put into standard form gives ...
... 3x^2 -8x -3 = 0
This can be factored as ...
... (3x +1)(x -3) = 0
so the values of x that make these factors zero are ...
... x = -1/3 . . . and . . . x = 3
The original equation requires x > 1, so the only viable solution here is ...
... x = 3
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We can also solve this graphically to get the same result.
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