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VashaNatasha [74]
3 years ago
10

g The Sharpe Ratio measures: Select one: The risk of an investment The expected return of an investment The unexpected return; h

ow much an investment over- or under-performed The extra return above the risk-free rate adjusted for systematic risk The extra return above the risk-free rate adjusted for total risk The extra return above the risk-free rate adjusted for unsystematic risk The raw return adjusted for the return on the market
Business
1 answer:
NISA [10]3 years ago
3 0

Answer:

The extra return above the risk-free rate adjusted for total risk

Explanation:

The Sharpe Ratio was developed by William Sharpe, and it is used by investors to guage the return in an investment against risk.

To calculate it we find the excess return above risk free rate And divide it by the total risk.

This isolates the returns that are attributed to risk taking activity.

A risk free transaction for example is the yield on government treasury bills.

We use only returns associated with risk to get a better picture of risk adjusted return. The higher the ratio the better.

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Suppose that an investor is considering three alternative strategies: conservative, neutral, or aggressive. If economic conditio
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The answer is: Following the expected value criterion the investor should choose indistinctively between the conservative or neutral alternatives.

Explanation:

The formula we use to calculate the expected return value of the different alternatives is:

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3 years ago
Automobile repair costs continue to rise with the average cost now at $367 per repair.† Assume that the cost for an automobile r
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Answer:

a)  0.1728

b)  0.09183

c) 0.7354

d) $ 222.25

Explanation:

Given

mean = \mu = $367

Standard deviation = \sigma =$88

Cost of automobile repair is normally distributed.

a) We have to find P( x > 450 )

P( x > 450 ) = 1 - P( x <= 450 )

Using excel function,   P( x <= x ) = NORMDIST (x,  \mu, \sigma, 1 )

P( x > 450 )   = 1 - NORMDIST( 450 , 367, 88, 1 )

= 1 - 0.8272 = 0.1728

P( x > 450 ) = 0.1728

b)  P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( x < 250 ) = 0.09183

c) P( 250 < x < 450 ) = P( x <450 ) - P( x < 250 )

P( x <450 ) = NORMDIST( 450 , 367, 88, 1 ) = 0.8272

P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( 250 < x < 450 ) = 0.8272 - 0.09183 = 0.7354

P( 250 < x < 450 ) = 0.7354

d) We have P( X < a ) = 0.05

We have to find a.

Using Excel, = NORMINV ( Probability, \mu, \sigma )

a = NORMINV ( 0.05 , 367, 88 ) = 222.2529

Cost = $ 222.25

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