Answer:
Carl has to sell at least cookies.
Step-by-step explanation:
Carl gets by selling 1 chocolate bar.
Earning from chocolate bars:
Earning From cookies:
Carl wants to raise at least
Given that (p - 1/p) = 4, the value of p² + 1/p² is 18. Detail below
<h3>Data obtained from the questio</h3>
- (p - 1/p) = 4
- p² + 1/p² = ?
<h3>How to determine the value of p² + 1/p²</h3>
(p - 1/p) = 4
Square both sides
(p - 1/p)² = (4)²
(p - 1/p)² = 16 ....(1)
Recall
(a - b)² = a² + b² - 2ab
Thus,
(p - 1/p)² = p² + 1/p² - (2 × p × 1/p)
(p - 1/p)² = p² + 1/p² - 2
From equation (1) above,
(p - 1/p)² = 16
Therefore,
p² + 1/p² - 2 = 16
Rearrange
p² + 1/p² = 16 + 2
p² + 1/p² = 18
Thus, the value of p² + 1/p² is 18
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It would remain the same (4/5). <span>Sin of the angle is unchanged regardless of the size; it is a ratio related only to the angle, not the size of the triangles.</span>
Answer:
On Saturday, a local hamburger shop sold a combined total of 312 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold, How many hamburgers were sold on Saturday?
Step-by-step explanation:
x is the hamburgers
x times 3 is the cheeseburgers
answer x=78
check work 78 x 3 =234
78 + 234 = 312
<h2>
<u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>
Given system of linear equations are ,
And we need to find the Solution of the linear equation . So let's Firstly number the equations .
<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>
=> 3 ( x + y ) = 2*3
=> 3x + 3y = 6
<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>
=> 3x + 3y -3y + y = 6 + 2
=> 4y = 8
=> y = 8/4
=> y = 2
<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>
=> x + y = 2
=> x + 2 = 2
=> x = 2- 2
=> x = 0
<h3>
<u>★</u><u> </u><u>Hence</u><u>
the required solution is ( 0 , 2 ) .</u></h3>