Answer:
4,5,6 are the three consecutive numbers. 16, 25 and 36 are their squares.
Step-by-step explanation:
Let the three consecutive numbers be x, (x+1), (x+2)
Now, the squares of these three numbers are 
Sum = 77
∴by the problem ,

{Taking 3 common }

{By factorization}

Therfore,

<em>X can't be negetive </em>
∴ 
The squares of the three consecutive numbers are 16, 25, 36
The three consecutive numbers whose sum is 77 are 4, 5, 6
Answer:
x < -15
Step-by-step explanation:
Here is the solution:
-3x-42 > 3
Add the numbers
-3x > 45
Divide both sides of the inequation by -3 and flip the inequality sign.
x < -15
Here is the answer in the picture