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GarryVolchara [31]
3 years ago
15

Based on the graph, what is the initial value of the linear relationship? A coordinate plane is shown. A line passes through the

x-axis at negative 3 and the y-axis at 5. Select one: a. −4 b. −3 c. five over three. d. 5
Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0
<h3>Answer:</h3>

d. 5

<h3>Explanation:</h3>

The "initial value" is the value where the line crosses the y-axis (5). This is the place where the independent variable (x) is zero, the starting place for that variable.

Vsevolod [243]3 years ago
5 0

Answer:

d. 5

Step-by-step explanation:

We are asked to find the initial value of the linear relationship. The given relationship is: A line passes through the x-axis at negative 3 and the y-axis at 5.

We know that the initial value of function is known as the y-intercept of a function. We know that y-intercept of a graph is the point, where line intersects or crosses y-axis.

Since we have been given that line passes through y-axis at 5, therefore, the initial value of the linear relationship is 5 and option "d" is the correct choice.

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Step-by-step explanation:

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Read 2 more answers
What is the solution to<br> 4(2x– 3)= 2(3x+ 1)?<br><br><br> -5<br><br> 1<br><br> 7<br><br> 10
Paul [167]
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<span>(4 (2x – 3)= 2( 3x + 1)) </span>÷ 2
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3 years ago
The Department of Transportation would like to test the hypothesis that the average age of cars on the road is less than 12 year
puteri [66]

Answer:

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Step-by-step explanation:

information given

\bar X=10.6 represent the sample mean  

\sigma=4.1 represent the population standard deviation

n=45 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value for the test

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Replacing the info given we got:

We can replace in formula (1) the info given like this:  

z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29  

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